Haloalkanes & Haloarenes Test

Result

Haloalkanes & Haloarenes Test - 12

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0.25

Consider the following reaction,

Q.

When a pure enantiomer of X is taken in the above reaction, correct completion regarding the reaction is/are

A
Four different dichlorocyclohexane are formed as significant products

B
a pair of enantiomers is formed

C
two pairs of diastereomers are formed

D
Option A,C are Correct

Solution
Question 2
1 / -0.25

Choose the correct statement(s) from the following regarding free radical chlorination and bromination reaction of alkane.

A
The first propagation step is exothermic in bromination reaction and endothermic in chlorination reaction

B
The first propagation step is endothermic in bromination reaction and exothermic in chlorination reaction

C
Chlorination reaction is more reactive process but very less selective, reverse is true for bromination

D
Option B,C are Correct

Solution

In free radical halogenation of alkane, the first step of propagation is exothermic when Cl₂ is used while it is endothermic when Br₂ is used. Also chlorination occur at very fast rate, hence very less selective while bromination occur at very slow rate, occurs selectively where most stable free radical is formed.
Question 3
1 / -0.25

Comprehension Type

Direction (Q. Nos. 3 - 5) This section contains a paragraph, describing theory, experiments, data, etc.
Three questions related to the paragraph have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).

Passage

An alcohol (R —OH) can be converted into alkyl chloride by the treatm ent with HCI. Reaction involves protonation of alcohol followed by the formation of carbocation intermediate. Carbocation intermediate in the final step undergo nucleophilic attack by Cl^- ion as :

Q.

Which of the following alcohol reacts most easily?

A

B

C

D

Solution

As mentioned in mechanism, reaction proceed via carbocation intermediate. Hence, alcohol forming most stable carbocation reacts most easily. Alcohol (c) forms aromatic (highly stable) carbocation, hence most reactive.
Question 4
1 / -0.25

An alcohol (R —OH) can be converted into alkyl chloride by the treatm ent with HCI. Reaction involves protonation of alcohol followed by the formation of carbocation intermediate. Carbocation intermediate in the final step undergo nucleophilic attack by Cl^- ion as :

Q.

Which of the following can catalyse the above reaction?

A
AgNO₃

B
ZnCl₂

C
CCl₄

D
H₃ PO₄

Solution

ZnCI₂ is a Lewis acid, helps in the form ation of carbocation intermediate, hence catalyse the reaction.
Question 5
1 / -0.25

An alcohol (R —OH) can be converted into alkyl chloride by the treatm ent with HCI. Reaction involves protonation of alcohol followed by the formation of carbocation intermediate. Carbocation intermediate in the final step undergo nucleophilic attack by Cl^- ion as :

Q.

What is the correct order of reactivty of the followings with HCl?

A
I < II < III < IV

B
IV < II< III< I

C
III < II < I < IV

D
IV < I < II < III

Solution

The order of stability of carbocation intermediates formed follows the order of reactivity.
Question 6
1 / -0.25

One Integer Value Correct Type

Direction (Q, Nos. 6 - 9) This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).

Q.

If 2,4-dimethyl pentane is subjected to free radical chlorination reaction, how many different monochlorinated products would be formed?

A
4

B
3

C
2

D
1

Solution
Question 7
1 / -0.25

On free radical chlorination reaction of butane, how many different, optically active, dichloroalkanes would be formed ?

A
5

B
6

C
7

D
8

Solution

Only three pairs of enantiomers are formed.
Question 8
1 / -0.25

If 1, 3-butadiene is treated with excess of bromine in CCI₄ , how many different tetrabromides would be formed?

A
1

B
2

C
3

D
0

Solution
Question 9
1 / -0.25

Consider the following reaction,

Q.

How many different monobromo derivatives would be produced?

A
1

B
2

C
0

D
4

Solution

(I) has two optically active enantiomers and (II) has two geometrical isomers.