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Aldehydes and Ketones Test - 6

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Aldehydes and Ketones Test - 6
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  • Question 1
    1 / -0.25

     

    Consider the following reaction,

    (A pure enantiomer)

    Q. 

    The incorrect statement regarding X is

     

    Solution

     

     

     X will be a pure enantiomer of aldehyde.

     

     

  • Question 2
    1 / -0.25

     

    Consider the following reaction sequence,

    Q. 

    The correct statement regarding X is

     

    Solution

     

     

     

     

  • Question 3
    1 / -0.25

     

    One or More than One Options Correct Type

    Direction : This section contains 5 multiple choice questions. Each question has four choices (a), (b), (c) and (dj, out of which ONE or MORE THAN ONE are correct.

    Q. 

    In which of the following reactions, an aldehyde is formed as major product?

     

    Solution

     

     

    (b) In option (b), aldehyde is not formed. When a terminal alkyne is oxidised with KMnO4 , a carboxylic acid is always formed.
    All options are preparation of aldehydes.

     

     

  • Question 4
    1 / -0.25

     

    In which of the following reactions, ketone is formed as the major organic product?

     

    Solution

     

     

    If acid derivatives like nitrile, acid chlorid e or ester is taken in excess in Grignard synthesis, second addition of Grignard ’s reagent on carbonyl product does not succeed and carbonyls are obtained as major products.
    In option (b), carboxylic acids and in option (d), an aldehyde is formed.

     

     

  • Question 5
    1 / -0.25

     

    Consider the following reaction,

    Q. 

    The correct statement(s) regarding the above reaction is/are

     

    Solution

     

     


    Trans diastereomer of the above diol does not react due to its inability to form cyclic intermediate.

     

     

  • Question 6
    1 / -0.25

     

    Consider the reaction mentioned below,

    Q. 

    The expected organic product(s) is/are

     

    Solution

     

     

    Formylation of double bond (oxo process) occurs. However, the reaction is not regioselective, hence both isomers of aldehyde are formed.

     

     

  • Question 7
    1 / -0.25

     

    Consider the following reaction, 

    Q. 

    Reagent(s) that can bring about the above reaction successfully is/are

     

    Solution

     

     

    Both Rosenmund reduction (Pd/BaSO4 )and reduction with Li[{(CH3 )CO}3 AIH] at - 80 °C are effective in reducing acid chlorides into aldehydes.

     

     

  • Question 8
    1 / -0.25

     

    Comprehension Type

    Direction : This section contains a paragraph, describing theory, experiments, data, etc. Three questions related to the paragraph have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).

    Passage

    A hydrocarbon A (C10 H18 ) is capable of showing both enantiomerism as well as diastereomerism. Treatment of A either with HgSO4 / H2 SO4 or B2 H6   / H2 O2 -NaOH results in the same carbonyl compound B. Also,

     C can also be obtained as one of the  product in the following reaction.

    Q. 

    What is the most likely structure of B?

     

    Solution

     

     

    Compound A has a triple bond and it is symmetrical because its partially reduced product B gives single ozonolysis product C, Also, A shows both enantiomerism and diastereomerism, it must be

    As shown above, A has two chiral carbons but simultaneously, it is symmetrical. Hence, it has both meso and a pair of enantiomers as stereoisomers.

     

     

  • Question 9
    1 / -0.25

     

    A hydrocarbon A (C10 H18 ) is capable of showing both enantiomerism as well as diastereomerism. Treatment of A either with HgSO4 / H2 SO4 or B2 H6   / H2 O2 -NaOH results in the same carbonyl compound B. Also,

     C can also be obtained as one of the  product in the following reaction.

    Q. 

    What is the structure of compound C?

     

    Solution

     

     

    Compound A has a triple bond and it is symmetrical because its partially reduced product B gives single ozonolysis product C, Also, A shows both enantiomerism and diastereomerism, it must be

    As shown above, A has two chiral carbons but simultaneously, it is symmetrical. Hence, it has both meso and a pair of enantiomers as stereoisomers.

     

     

  • Question 10
    1 / -0.25

     

    A hydrocarbon A (C10 H18 ) is capable of showing both enantiomerism as well as diastereomerism. Treatment of A either with HgSO4 / H2 SO4 or B2 H6   / H2 O2 -NaOH results in the same carbonyl compound B. Also,

     C can also be obtained as one of the  product in the following reaction.

    Consider the reaction given below,

    Q. 

    How many different alcohols are expected?

     

    Solution

     

     

    Compound A has a triple bond and it is symmetrical because its partially reduced product B gives single ozonolysis product C, Also, A shows both enantiomerism and diastereomerism, it must be

    As shown above, A has two chiral carbons but simultaneously, it is symmetrical. Hence, it has both meso and a pair of enantiomers as stereoisomers.

     

     

  • Question 11
    1 / -0.25

     

    One Integer Value Correct Type

    Direction : This section contains 5 questions. When worked out will result in an integer from 0 to 9 (both inclusive).

    Q. 

    How many different aldehyde isomers exist for C5 H10 O ?

     

    Solution

     

     

     

     

  • Question 12
    1 / -0.25

     

    How many different ketones isomer exist for C6 H12 O  ?

     

    Solution

     

     

     

     

  • Question 13
    1 / -0.25

     

    How many different alcohol isomers with molecular formula C5 H12 O  can be oxidised to ketones using K2 Cr2 O7 - H2 SO4 ?

     

    Solution

     

     

    All secondary alcohol isomers can be oxidised to ketones.

     

     

  • Question 14
    1 / -0.25

     

    If all the ketone isomers of C6 H10 O are reduced independently with NaBH4 , how many of them will produce racemic mixture of alcohols?

     

    Solution

     

     


    All the above shown ketones on reduction with NaBH4 will produce racemic mixtures of alcohols. The isomer below already has a chiral carbon, show enantiomerism. A pure enantiomer of this ketone, on reduction with NaBH4 , will produce pair of diastereomers.

     

     

  • Question 15
    1 / -0.25

     

    Consider the following reaction,


    Q. 

    How many different diols are expected at the end of the above reaction?

     

    Solution

     

     


     

     

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