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Matrices Test - 9

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Matrices Test - 9
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Weekly Quiz Competition
  • Question 1
    1 / -0.25

    The product of two matrics  

    Solution

    {(1*0, 2*2, 0*x) (2*0, 0*2, 1*x) (1*0, 0*2, 2*x)}
    = {4, x, 2x} 

  • Question 2
    1 / -0.25

    If A, B are, respectively m ×n, k ×l matrices, then both AB and BA are defined if and only if ​

    Solution

    If A, B are, respectively m ×n, k ×l matrices, then both AB and BA are defined if and only if n = k and l = m. In particular, if both A and B are square matrices of the same order, then both AB and BA are defined.

  • Question 3
    1 / -0.25

    and 2A + B + X = 0, then the matrix X = ……

    Solution

  • Question 4
    1 / -0.25

    If   then -5A = ?

  • Question 5
    1 / -0.25

    If    and  , then AXB=?

    Solution

    A = [2, 3, 4]  
    Therefore AXB = {(2*1) + (3*(-1)) + (4*2)}
    AXB = {2 + (-3) + 8}
    AXB = 7

  • Question 6
    1 / -0.25

    If    and  , then = 2A - B?

  • Question 7
    1 / -0.25

    If    and  , then AB = ?

    Solution


    A.B = [(-1(-1) + 2(-2) + 3(-3)  -1(-3) + 2(1) + 3(2)]

    A.B = [1 - 4 - 9   3 + 2 + 6]

    A.B = [-12  11]

  • Question 8
    1 / -0.25

    Solution

     P(n) : An = {(1+2n, -4n), (n,(1 - 2n))}
    = P(k + 1) = {(1+2(k+1), -4(k+1)), (k+1, (1 - 2(k+1)}
    = {(1+2k+2, -4k-4) (k+1, 1-2k-2)}
    = {(2k+3, -4k-4), (k+1, -2k-1)}

  • Question 9
    1 / -0.25

    Value of determinant is computed by adding multiples of one row to

    Solution

    Value of Determinant remains unchanged if we add equal multiples of all the elements of row (column) to corresponding elements of another row (column) If, we have a given matrix A.

  • Question 10
    1 / -0.25

    If    and  , then AB = ?

    Solution

    A = {(2),(3)}    B = {-1,2,-2}
    AB = {(-2,4,-4) (-3,6,-6)}

  • Question 11
    1 / -0.25

    For a skew symmetric even ordered matrix A of integers, which of the following will not hold true:

    Solution

    Determinant of a skew symmetric even ordered matrix A is a non zero perfect square.

  • Question 12
    1 / -0.25

    If A is a matrix of order 1 ×3 and B is a matrix of order 3 ×4, then order of the matrix obtained on multiplying A and B is ​

    Solution

    In matrix 1*3 is one row and 3 columns and in 3*4 is three rows and four column hence multiplied matrix will be 1*4.

  • Question 13
    1 / -0.25

    If    and  , then A-2B is equal to

    Solution

    A={(-1,2) (3,-2) (-4,3)}   B={(1,3) (3,-2) (6,2)}
    2B = {(2,6) (6,-6) (12,4)}
    A - 2B = {(-1,2) (3,-2) (-4,3)} - {(2,6) (6,-6) (12,4)}
    = {(-1-2, 2-6) (3-6, -2+4) (-4-12, 3-4)}
    = {(-3,-4) (-3,2) (-16, -1)}

  • Question 14
    1 / -0.25

    If    and   then AB = ?

  • Question 15
    1 / -0.25

    If A and B are two matrices conformable to multiplication such that their product AB = O(Zero matrix). Then which of the following can be true ​

    Solution

    AB = 0 does not necessarily imply that either A or B is a null matrix  
    - Both matrices need not be null matrices.

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