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Integrals Test - 4

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Integrals Test - 4
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  • Question 1
    1 / -0.25

    One value of  ∫f '(x) dx is  

    Solution

    As (∫f '(x)dx) = f(x) + C, therefore, one value of (∫f '(x) dx) is f(x)

  • Question 2
    1 / -0.25

    ∫ log x dx is equal to  

    Solution

  • Question 3
    1 / -0.25

    Solution


  • Question 4
    1 / -0.25

    Solution

  • Question 5
    1 / -0.25

    Solution


  • Question 6
    1 / -0.25

    if  ∫g(x) dx = g(x), then   is equal to  

    Solution

  • Question 7
    1 / -0.25

    If f (x) be a function such that  

    Solution

    ∫log xdx = xlog x - x = x(log x -1)

     = x(log x - log e) = 

  • Question 8
    1 / -0.25

    Solution


  • Question 9
    1 / -0.25

    Solution

    Dividing numerator and denominator by cos2x and substituting tanx = t , we get :

  • Question 10
    1 / -0.25

    Solution

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