Three-dimension...

The equation of the plane passing through the point (3, –3, 1) and perpendicular to the line joining the points (3, 4, –1) and (2, –1, 5) is:​

The equation of the plane, which is at a distance of 5 unit from the origin and has   as a normal vector, is:

The Cartesian form of the equation of the plane  is:

The length of the perpendicular from the origin to the plane 3x + 2y –6z = 21 is:​

The slope intercept form of the linear equation is

If l, m, n are the direction cosines of the normal to the plane and p be the perpendicular distance of the plane from the origin, then the equation of the plane is:

If    is the normal from the origin to the plane, and    is the unit vector along   . P(x, y, z) be any point on the plane and    is perpendicular to   . Then  

The length of the perpendicular from the origin to the plane 2x –3y + 6z = 21 is:​

The angle between two lines whose direction ratios are 1,2,1 and 2,-3,4 is:​

The equation of the plane passing through the points (2, 1, 0), (3, –2, –2) and (3, 1, 7) is:​