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Chemistry Test - 20

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Chemistry Test - 20
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  • Question 1
    5 / -1
    Fructose reduces Tollen's reagent due to
    Solution

    Explanation:

    Tollen's reagent-

    • Tollens Test is a very useful method to distinguish between aldehydes and ketones. This qualitative lab test is also referred to as the silver mirror test.
    • Tollens Reagent refers to the chemical reagent used to detect an aldehyde functional group, an aromatic aldehyde functional group, or an alpha-hydroxy ketone functional group in a given test substance.
    • Tollens test is generally given by compounds having an aldehydic group (aldehydes,alpha-hydroxy ketones, and formic acid-its -COOH behaves like an aldehydic group). It gives a white ppt of Silver (where the silver salt is reduced to silver metal and the aldehyde is oxidized to silver salt of carboxylic acid.

    Given data and Analysis-

    ⇒ Aldehydes are oxidized easily but ketones do not quickly oxidize by Tollen's agent.

    ⇒ Only aldehydes can reduce Tollen’s reagent.

    ⇒ Fructose is a Ketone, so fructose is kept in an aqueous solution and enolized. And then converted into aldehyde in the basic medium or by the base.

    ⇒ The reaction of aldehydes with Tollen’s reagent is an oxidation reaction.

    ⇒ All aldehydes generally reduce Tollen's reagent.

    ⇒ It can be concluded that fructose reduces Tollen’s reagent due to the enolization of fructose followed by conversion to aldehyde by the base.

  • Question 2
    5 / -1
    Glucose in blood can be quantitatively determined with
    Solution

    Explanation-

    Tollens test-

    • Tollens Test is a very useful method to distinguish between aldehydes and ketones. This qualitative lab test is also referred to as the silver mirror test.
    • Tollens test is generally given by compounds having an aldehydic group (aldehydes,alpha-hydroxy ketones, and formic acid-its -COOH behaves like an aldehydic group). It gives a white ppt of Silver (where the silver salt is reduced to silver metal and the aldehyde is oxidized to silver salt of carboxylic acid.

    Glucose-

    • Glucose is a simple sugar with six carbon atoms and one aldehyde group. This monosaccharide has a chemical formula C6H12O6.
    • The aldehydic group is present in glucose and Tollen's reagent is the test for aldehydes.
    • So Glucose in the blood can be quantitatively determined with Tollen's reagent.

    Important Points

    Benedict's solution-

    ⇒ Benedict’s test is a chemical test that can be used to check for the presence of reducing sugars in a given analyte.

    Alkaline iodine solution-

    ⇒ When Iodine and sodium hydroxide are added to a compound that contains either a methyl ketone or secondary alcohol with a methyl group in the alpha position, a pale yellow precipitate of iodoform or triiodomethane is formed. It can be used to identify aldehydes or ketones

    Bromine water-

    ⇒ Bromine water is a yellow mixture solution with high oxidizing properties, prepared by dissolving diatomic bromine (Br2) in water (H2O).

  • Question 3
    5 / -1

    The structure of D- (+) -glucose is

    The structure of L- (-) -glucose is

    Solution

    Explanation-

    • Glucose is a simple sugar with six carbon atoms and one aldehyde group. This monosaccharide has a chemical formula C6H12O6.
    • Glucose is a carbohydrate and an important biomolecule that helps in the metabolism of the body.
    • The glucose is reacted with acetic anhydride to form pentadactyl derivatives. This simply shows the presence of five hydroxyl groups. As we know Glucose is a very stable compound, no two OH groups can be attached to the same carbon.
    • Or in other words, we can say that the five OH groups are present on the different carbons.
    • D - glucose and L - glucose yield the same dicarboxylic acid: This means that these two sugars differ only in respect of the position of the terminal groups (CHO and CH2OH).

    ∴ The exchange of the terminal groups in D-glucose should be able to give a different aldohexose.

    • L- (-) -glucose is the enantiomer of the more common D-glucose.

    The structure of L- (-) -glucose is

      

  • Question 4
    5 / -1
    Schweitzer's reagent used for dissolving cellulose in the manufacture of artificial silk is
    Solution

    Explanation:

    Reagent-

    • A reagent is a compound or mixture added to a system to start or test a chemical reaction. A reagent can be used to determine the presence or absence of a specific chemical substance as certain reactions are triggered by the binding of reagents to the substance or other related substances.

    Schweizer's reagent-

    • Schweizer's reagent is the metal ammine complex with the formula [Cu(NH3)4(H2O)2](OH)2.This deep-blue compound is used in purifying cellulose.
    • It is prepared by precipitating copper(II) hydroxide from an aqueous solution of copper sulfate using sodium hydroxide or ammonia, then dissolving the precipitate in a solution of ammonia.
    • Schweitzer's reagent used for dissolving cellulose in the manufacture of artificial silk is [Cu(NH3)4]SO4.
  • Question 5
    5 / -1

    In the following structure,

    anomeric carbon is

    Solution

    Explanation:

    Anomeric carbon-

    • An anomeric carbon is a hemiacetal or hemiketal carbon of cyclic sugar. It is the carbon at which the alpha anomer or beta anomer is formed.
    • An anomeric carbon can be identified as the carbonyl carbon (of the aldehyde or ketone functional group) in the open-chain form of the sugar. It can also be identified as the carbon bonded to the ring oxygen and a hydroxyl group in the cyclic form.
    Given data and Analysis:
    ⇒ In the cyclic form of sugar, the anomeric carbon is the carbon that was part of the carbonyl group in the straight-chain structure.
    ⇒ When the chain converts to a ring, C−1 becomes a chiral center.
    ⇒ C − 1 is the anomeric carbon.

    ⇒ C - 1 is an anomeric carbon and due to this, it exists in two forms, α, and β.

  • Question 6
    5 / -1
    Which one of the following statements is not true regarding (+) Lactose
    Solution

    Explanation-

    Lactose-

    ⇒ Lactose is a disaccharide that upon hydrolysis gives two saccharides, glucose and galactose. It was discovered by Fabriccio Bartoletti and is a solid carbohydrate that is white in color. 2-8% of milk contains lactose and this is the natural form of sugar present in it.

    ⇒ The structural formula of lactose is as shown in the figure.

    (+) Lactose, C12H22O11 contains 8-OH groups.

    ⇒ On hydrolysis (+) Lactose gives an equal amount of D(+) glucose and D(+) galactose.

    ⇒ (+) Lactose is a β-glycoside formed by the union of a D(+) glucose and a molecule of D(+) galactose.

    ⇒ (+) Lactose is a reducing sugar and all reducing sugar shows mutarotation.

  • Question 7
    5 / -1
    Sanger's reagent is used for the identification of
    Solution

    Explanation-

    • A reagent is a substance or compound added to a system to cause a chemical reaction, or added to test if a reaction occurs. Sanger's reagent is 1-Fluoro-2,4-dinitrobenzene (commonly called, dinitrofluorobenzene, DNFB, or FDNB).
    • Sanger’s reagent reacts with the peptide chain and undergoes nucleophilic aromatic substitution (NAS) with the N-terminal amino group of a peptide or protein, resulting in a chemical tag on the terminal amino acid residue.
    • Then the product is hydrolyzed into individual amino acids, the peptide or protein's terminal amino acid can be identified by the specific wavelength of light absorbed (i.e., colorimetric analysis).
    • Sanger’s reagent reacts with the N-terminal of the amino acid.
    • So Sanger's reagent is used for the identification of the N-terminal amino acid of the peptide chain.

     Important Points

    Colorimetric analysis-

    • A colorimeter is a device that is used in Colorimetry. It refers to a device that helps specific solutions to absorb a particular wavelength of light.
    • The colorimeter is usually used to measure the concentration of a known solute in a given solution with the help of the Beer-Lambert law.
    • There are two types of colorimeters — color densitometers, which measure the density of primary colors, and color photometers, which measure the color reflection and transmission.
  • Question 8
    5 / -1
    Denaturation of protein
    Solution

    Explanation-

    Denaturation of protein-

    Denaturation implies the destruction of the tertiary structure of a protein molecule and the formation of random polypeptide chains.

    • Secondary, tertiary and quaternary protein structure is easily changed by a process called denaturation. These changes can be quite damaging.
    • Heating, exposure to acids or bases and even violent physical action can cause denaturation to occur.
    • The albumin protein in egg white is denatured by heating so that it forms a semisolid mass. Almost the same thing is accomplished by the violent physical action of an egg beater in the preparation of meringue.
    • Heavy metal poisons such as lead and cadmium change the structure of proteins by binding to functional groups on the protein surface.
    • Denaturation of proteins can be done by bringing in physical changes as well as the introduction of chemicals.
    • Most of the denaturation processes are irreversible, but it has been seen (in very few cases) that some of the denaturation processes can be reversed; it is then called as renaturation of protein.
    • Some of the common cases of denaturation of proteins are coagulation of egg white when an egg is subjected to boiling. Here the denaturation occurs due to a change in temperature.
  • Question 9
    5 / -1
    Identify the correct statement regarding enzymes
    Solution

    Explanation-

    ⇒ Enzymes can be defined as biological polymers that catalyze biochemical reactions.

    ⇒ Most enzymes are proteins with catalytic capabilities crucial to performing different processes. Metabolic processes and other chemical reactions in the cell are carried out by a set of enzymes necessary to sustain life.

    ⇒ Enzymes are a linear chain of amino acids, which give rise to a three-dimensional structure. The sequence of amino acids specifies the structure, which in turn identifies the catalytic activity of the enzyme.

    ⇒ Upon heating, the enzyme’s structure denatures, resulting in a loss of enzyme activity, which typically is associated with temperature.

    ⇒ Enzymes are said to possess an active site. The active site is a part of the molecule that has a definite shape and the functional group for the binding of reactant molecules.

    ⇒ The molecule that binds to the enzyme is referred to as the substrate group. The substrate and the enzyme form an intermediate reaction with low activation energy without any catalysts.

    ⇒ The effectiveness of a catalyst is maximum at its optimum temperature. The activity of the biochemical catalysts declines at either side of the optimum temperature.

  • Question 10
    5 / -1
    Which one of the following, statements is incorrect about enzyme catalysis
    Solution

    Explanation:

    Enzyme catalysis:

    ⇒ Catalysis is a phenomenon in which the rate of the reaction is altered with the help of a substance called a catalyst (the catalyst does not participate in the reaction; its concentration and composition remain unchanged).

    ⇒ The substance used to change the rate of the reaction is called a catalyst. Enzymes are a class of catalysts that are responsible for facilitating and increasing the rate of many vital biochemical reactions in plants and animals.

    The catalysis in which enzymes act as a catalyst is called enzyme catalysis.

    • A single molecule of the enzyme catalyst can transform up to a million molecules of the reactant per second. Hence, enzyme catalysts are said to be highly efficient.
    • These biochemical catalysts are unique to certain types of reactions, i.e. the same catalyst cannot be used in more than one reaction.
    • The effectiveness of a catalyst is maximum at its optimum temperature. The activity of the biochemical catalysts declines at either side of the optimum temperature.
    • Enzymes are mostly proteinous in nature. Enzymes are denatured by ultraviolet rays and at high temperatures.
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