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Chemistry Test - 34

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Chemistry Test - 34
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  • Question 1
    5 / -1

    Directions For Questions

    The following statements describe the properties of a fuel cell:

    (A) A fuel cell directly converts the chemical energy of a fuel into electrical energy

    (B) The overall cell reaction in a hydrogen-oxygen fuel cell is: 2H2(g) + O2(g) --> 2H2O(l)

    (C) A fuel cell requires continuous charging like a secondary battery

    (D) Fuel cells produce water as the only by-product and are considered environmentally friendly

    ...view full instructions

    Choose the correct answer from the options given below:

    Solution

    A fuel cell is an electrochemical device that directly converts the chemical energy of a fuel (such as hydrogen) into electrical energy, making statement (A) correct. The net cell reaction in a hydrogen-oxygen fuel cell is 2H2(g) + O2(g) --> 2H2O(l), confirming statement (B). Statement (C) is incorrect because a fuel cell is not rechargeable; it continuously generates electricity as long as fuel and oxidant are supplied from external sources. Statement (D) is correct because the only by-product of a hydrogen-oxygen fuel cell is water, which makes it a clean and eco-friendly energy device.

     

  • Question 2
    5 / -1

    Directions For Questions

    The following statements describe Kohlrausch's law and molar conductivity of electrolytes:

    (A) Kohlrausch's law states that the molar conductivity of an electrolyte at infinite dilution is the sum of the individual ionic conductances of cations and anions

    (B) Molar conductivity of strong electrolytes increases sharply with dilution

    (C) Kohlrausch's law can be used to calculate the molar conductivity at infinite dilution of weak electrolytes, which cannot be determined experimentally

    (D) The degree of dissociation of a weak electrolyte can be calculated using Kohlrausch's law

    ...view full instructions

    Choose the correct answer from the options given below:

    Solution

    Kohlrausch's law of independent migration of ions states that the molar conductivity of an electrolyte at infinite dilution is the algebraic sum of the limiting molar conductivities of its individual ions, confirming statement (A). Statement (B) is incorrect; for strong electrolytes, molar conductivity increases only gradually and linearly with dilution (following Debye-Huckel-Onsager equation), not sharply. Weak electrolytes, such as acetic acid, cannot be brought to infinite dilution experimentally, but their limiting molar conductivity can be calculated using Kohlrausch's law by summing the ionic contributions, making statement (C) correct. Using the ratio of molar conductivity at a given concentration to the limiting molar conductivity gives the degree of dissociation, confirming statement (D).

     

  • Question 3
    5 / -1

    Solution

    The lead storage battery is a secondary (rechargeable) cell widely used in automobiles, operating on lead and lead dioxide electrodes in sulphuric acid (II). The nickel-cadmium battery is also a rechargeable secondary battery, commonly used in portable electronics (III). Corrosion is the process of oxidation of metals — methods like galvanisation and painting are used to prevent rusting (I). Faraday's laws of electrolysis relate the mass of substance deposited at an electrode to the quantity of electricity passed through the electrolyte (IV).

     

  • Question 4
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    Solution

    For a zero order reaction, the rate constant has units of mol L-1 s-1, since rate = k and rate has these units (II). For a first order reaction, the rate constant k has units of s-1, derived from rate = k[A] (I). For a second order reaction, the units of k are L mol-1 s-1, obtained from rate = k[A]2 (III). A pseudo first order reaction is one that is higher order overall but appears first order because one reactant is in large excess and its concentration remains effectively constant (IV).

     

  • Question 5
    5 / -1

    Directions For Questions

    Arrange the following reactions in decreasing order of rate of reaction at the same temperature, given their activation energies (Eₐ):

    (A) Eₐ = 10 kJ/mol

    (B) Eₐ = 80 kJ/mol

    (C) Eₐ = 50 kJ/mol

    (D) Eₐ = 30 kJ/mol

    ...view full instructions

    Choose the correct order:

    Solution

    According to the Arrhenius equation, k = A·e^(−Eₐ/RT). The rate constant (and hence the rate) is inversely related to activation energy — a lower activation energy means a larger fraction of molecules have sufficient energy to react, resulting in a faster reaction. Therefore, the reaction with the lowest Eₐ has the highest rate: Eₐ = 10 < 30 < 50 < 80 kJ/mol means rate (A) > (D) > (C) > (B).

     

  • Question 6
    5 / -1

    Directions For Questions

    Arrange the following transition metals in increasing order of their first ionisation enthalpy:

    (A) Cr

    (B) Zn

    (C) Sc

    (D) Fe

    ...view full instructions

    Choose the correct order:

    Solution

    First ionisation enthalpies (approximate values): Sc ≈ 631 kJ/mol, Fe ≈ 762 kJ/mol, Cr ≈ 653 kJ/mol (slightly higher than Sc due to half-filled 3d stability), and Zn ≈ 906 kJ/mol (highest among 3d metals due to fully filled 3d¹⁰ configuration which offers extra stability). Therefore, the increasing order is: Sc < Fe < Cr < Zn, i.e., (C) < (D) < (A) < (B).

     

  • Question 7
    5 / -1

    Which one of the following elements is NOT a Lanthanoid?

    Solution

    Concept:

    • Our periodic table as given by Moseley and has in total 7 periods running horizontally and 18 groups running vertically.
    • They are also further divided into s, p, d, and f blocks depending on the placement of the outermost electrons.
    • Elements belonging to the same blocks resemble in their chemical and physical properties.
    • The s block elements lie in the 1st and 2nd groups.
    • The p block elements belong to groups 13-18.
    • The d and f block elements lie in the middle of group numbers 3-12.

    Explanation:

     

  • Question 8
    5 / -1

    The incorrect statement among the following is :

    Solution

    A: Correct. Actinoids are highly reactive metals, especially in powdered form, due to their low ionization energies and large atomic sizes.

    B: Correct. Actinoid contraction (due to poor shielding by 5f electrons) is more significant than Lanthanoid contraction (due to 4f electrons).

    C: Incorrect. Many trivalent Lanthanoid ions (e.g., Pr³⁺, Nd³⁺, Er³⁺) are colored due to f-f electronic transitions, even in the solid state.

    D: Correct. Lanthanoids are good conductors of heat and electricity, like most metals.

    Thus, C is the wrong statement.

     

  • Question 9
    5 / -1

    Directions For Questions

    ...view full instructions

    Choose the correct answer from the options given below:

    Solution

    Wurtz Reaction: Couples two alkyl halides (R–X) with sodium in dry ether to form alkanes (R–R). E.g., 2R–Cl + 2Na → R–R + 2NaCl.

    Sandmeyer Reaction: Converts a primary aromatic amine (Ar–NH₂) to an aryl halide (Ar–X) via a diazonium salt (Ar–N₂⁺) treated with CuCl or CuBr. E.g., Ar–N₂⁺Cl⁻ + CuCl → Ar–Cl + N₂.

    Fittig Reaction: Couples two aryl halides (Ar–X) with sodium in dry ether to form biaryls (Ar–Ar). E.g., 2Ar–Cl + 2Na → Ar–Ar + 2NaCl.

    Gattermann Reaction: Converts benzene diazonium chloride (C₆H₅N₂⁺Cl⁻) to chlorobenzene or bromobenzene using copper powder with HCl or HBr. E.g., C₆H₅N₂⁺Cl⁻ + Cu/HCl → C₆H₅Cl + N₂. Without the lists, I assume:

    List I: (a) Wurtz, (b) Sandmeyer, (c) Fittig, (d) Gattermann

    List II: (i) Forms biaryls, (ii) Forms alkanes, (iii) Forms chlorobenzene, (iv) Forms aryl halides Matches:

    (a) → (ii): Wurtz → Forms alkanes

    (b) → (iv): Sandmeyer → Forms aryl halides

    (c) → (i): Fittig → Forms biaryls

    (d) → (iii): Gattermann → Forms chlorobenzene

    Thus, the correct answer is A ((a) → (ii), (b) → (iv), (c) → (i), (d) → (iii)).

     

  • Question 10
    5 / -1

    Directions For Questions

    Directions: Read the following passage carefully:

    Molal boiling point elevation constant is the elevation in boiling point when the molality of solution is unity i.e., 1 mol of solute is dissolved in 1 kg (1000 g) of the solvent. The units of molal elevation constant is degree molality–1 i.e., K molal–1 or ºC molal–1 or K kg mol–1. It is denoted by Kb . The cause of elevation in boiling point is the vapor pressure of the solution is lower than that of pure solvent. Hence, when the non-volatile solute is added to pure solvent, the solution has to be heated more to make vapor pressure equal to the atmospheric pressure. Molal freezing point elevation constant is the depression in freezing point when the molality of the solutions is unity i.e., 1 mol of the solute is dissolved in 1000 g (1 kg) of the solvent. It is denoted by Kf . The unit of Kf is degree molality–1 i.e., K molal–1 or K kg mol–1 . The cause of depression in freezing point is the vapor pressure of the solution is less than that of pure solvent. Freezing point of a substance is the temperature at which the solid and the liquid forms of the substance are in equilibrium i.e., the solid and the liquid forms of substance have the same vapor pressure. Therefore, for the solution, this will occur at a lower temperature.

    ...view full instructions

    Ethylene glycol (C2H6O2 ) is used as an antifreeze. What mass of ethylene glycol should be added to 5.00 kg of water to lower the freezing point to –5.0 ºC?

    Given that Kf = 1.86 ºC molal–1. Consider ethylene glycol to be a non-electrolyte.

    Solution
    • Concept:
    • The freezing point of a substance may be defined as the temperature at which the vapour pressure of the substance in its liquid phase is equal to its vapour pressure in the solid phase.
    • When a non-volatile solid is added to the solvent its vapour pressure decreases and now it would become equal to that of solid solvent at lower temperature.
    • Thus, the freezing point of the solvent decreases. 
    • It is given by expression:
    • where ΔTf is the freezing point of pure solvent and Tf is its freezing point when a non-volatile solute is dissolved is known as depression in freezing point.
    • Expression: ΔTf = Kf. m
    • Kf is known as Freezing Point Depression Constant or Molal Depression Constant or Cryoscopic Constant, m is the molality.

    Given that ΔTf = 5.0 ºC

    and Kf = 1.86 ºC molal–1 .

    Therefore, molality is

    Molality = ΔT/Kf

    = 5.0/1.86

    = 2.7/molal

    Therefore, the number of moles of ethylene glycol is found from the relation 

    2.7 = n/5.0

    ⇒ n = 13.5 mol

    Molar mass of ethylene glycol is = 2 × 12 + 4 × 1 + 2 × 16 = 62 g mol–1.

    Hence, the mass of ethylene glycol to be added to water is 

    13.5mol × 62g/mol

    = 837 g

    Thus, the mass of ethylene glycol should be added to 5.00 kg of water to lower the freezing point to –5.0 ºC will be 837 g.

     

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