Self Studies
Selfstudy
Selfstudy

Logical Reasoning Test - 5

Result Self Studies

Logical Reasoning Test - 5
  • Score

    -

    out of -
  • Rank

    -

    out of -
TIME Taken - -
Self Studies

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Self Studies Self Studies
Weekly Quiz Competition
  • Question 1
    5 / -1
    Which of the following is not leap century year?
    Solution

    Leap century year is a leap year in the calendar which is divisible by 4 as well as 400 without a remainder. Like all leap years, it has an extra day in February.

    Leap year is a calendar year which is divisible by 4. Leap year contains an additional day in February. Every leap year has 29 days in February while ordinary year has 28 days in February. 

    The century year which is divisible by 400 without leaving remainder is known as leap century year.

    Checking in options:

    1. 2000 → 2000 is divisible by 400. Hence, it is leap century year.

    2. 1800 → 1800 is not completely divisible by 400. Hence, it is not a leap century year.

    3. 1200 → 1200 is divisible by 400. Hence, it is leap century year.

    4. 1600 → 1600 is divisible by 400. Hence, it is leap century year.

    Therefore, 1800 is not a leap century year.

    Hence, the correct answer is 1800.
  • Question 2
    5 / -1
    The day on 25 January 1950 will be:
    Solution
    No. of Odd daysOrdinary YearLeap Year
    365 ÷ 7 = 52 weeks + 1 odd day366 ÷ 7 = 52 weeks + 2 odd day

     

    YearsNo. of odd days
    100 years5
    200 years3
    300 years1
    400 years0

     

    Note: Multiple of 400 years i.e. 800, 1200, 1600, 2000 have 0 odd days.

    Calculating leap year: For Finding the number of leap year (1 - 99) years, divide the number of years by 4 and the quotient will be the number of leap years.

    Code for weekdays:

    No. of odd daysDay
    0Sunday
    1Monday
    2Tuesday
    3Wednesday
    4Thursday
    5Friday
    6Saturday

     

    1950 = we find out the odd days (the nearest leap century year + the nearest century year + completing year) = 1600 + 300 + 49

    • In 1600 year the odd days = 0
    • In 300 year the odd days = 1
    • In 49 years, odd days = 49/4 = 12 leap years and 37 ordinary years
      • In 12 leap years, no. of odd days = 24
      • In 37 ordinary years, no. of odd days = 37
    • So total = 24 + 37 = 61 odd days i.e. 61/7 = 5 odd days (remainder)
    • Odd days in January = 25 i.e. 4 odd days

    Total = 0 + 1 + 5 + 4 = 10 days = 3 odd days i.e Wednesday.

    As the code of Wednesday is 3.

    Hence, Wednesday is the correct answer. 

  • Question 3
    5 / -1
    Find the angle between the hour hand and the minute hand of a clock when the time is 3.30.
    Solution

    The logic followed here is:

    Given Time: 3:30

    Angle formula is: 11M/2 - 30H

    H(Hour) = 3, M(Minute) = 30

    Now, 11 × 30/2 - 30 × 3

    = 165 - 90

    75

    Hence, the correct answer is "75".

    Alternate Method

    Time = 3: 30

    \(Angle\;\left( \theta \right) = \left| {\frac{{60\; \times \;hour - \;11\; \times \;minute}}{2}} \right|\)

    And another angle = (360 - \(\theta )^∘ \)

    \(\therefore \;\theta = \;\left| {\frac{{60\; \times \;3 - \;11\; \times \;30}}{2}} \right|^∘ \)

    \( = \;\left| {\frac{{180 - 330}}{2}} \right|^∘ \)

    \( = \;\left| {\frac{{150}}{2}} \right|^∘ \)

    \( = \;75^∘ \)

    And another angle = (360 - \(\theta )^∘ \) = (360 - \(75)^∘ \) = 285

    In the option, 75 is given.

    Hence, ‘75’  is the correct answer.
  • Question 4
    5 / -1
    The calendar for the year 2018 is the same for the year:
    Solution

    Year

    Same Calendar for the year

    Year just after a leap year

    Add 6

    2nd year after a leap year

    Add 11

    3rd year after a leap year

    Add 11

    Leap Year

    Add 28


    1) 2007 → Leap year before 2007 is 2004, so 2007 is the 3rd year after a leap year.

    Same calendar for the year 2007 will be (2007 + 11) = 2018.

    2) 2006 → Leap year before 2006 is 2004, so 2006 is the 2nd year after a leap year.

    Same calendar for the year 2006 will be (2006 + 11) = 2017.

    3) 2008 → It is a leap year.

    Same calendar for the year 2008 will be (2008 + 28) = 2036

    4) 2009 → Leap year before 2009 is 2008, so 2009 is a year after a leap year.

    Same calendar for the year 2009 will be (2009 + 6) = 2015.

    Hence, ‘2007’ is the correct answer.
  • Question 5
    5 / -1
    If Seema's birthday is on 22 April which is Monday and Rajat's birthday is on 12 June of the same year. Which day of the week is Rajat’s birthday?
    Solution

    We know on 22 April = Monday

    And the number of days from 22 April to 12 June = 8 + 31 + 12 = 51 days

    When 51 is divided by 7, 2 is the remainder.

    Monday + 2 days = Wednesday

    Hence, Rajat’s birthday is on ‘Wednesday’.

  • Question 6
    5 / -1
    A clock gains 6 minutes per day. If it is said right at 1 p.m. on Monday. then what is the actual time after 16 hrs.?
    Solution

    Clock gains 6 minutes in 24 hrs. i.e. in 24 hrs. it gains 6 minutes.

    Time difference = 16 hrs.

    So, the time gains = \(16\times6\over24\) = 4 minutes.

    The given time = 1 P.M. and after 16 hrs, it will be = 5 A.M.

    Therefore, the time = Tuesday at 4:56 A.M.

    Hence, the correct answer is Tuesday at 4:56 A.M.

  • Question 7
    5 / -1
    Find the mirror image of the clock when the time is 01:40 hrs?
    Solution

    For every mirror image based on a clock,

    Given :

    The clock shows the time = 1:40

    To find :

    Time is shown in the mirror image 

    Concept used :

    For mirror image

    (11 - hours) : (60 - minutes)

    Solution :

    Hours = 1

    Minutes = 40

    Mirror image = (11 - 1) : (60 - 40)

    ⇒ Mirror image = 10:20

    If it is 12 hrs clock, then subtract the given timing from 11:60 hrs.

    If it is 24 hrs clock, then subtract the given timing from 23:60 hrs.

    Hence, the real time will be 10:20.

  • Question 8
    5 / -1
    At what time, between 4’o clock and 5’0 clock will the hands of watch point in opposite directions?
    Solution

    The angle between the hour hand and minute hand = \(60H -11M\over2\)

    Here, H = hour M = minutes.

    Given H = 4 and minutes = M and angle = 180°

    So, 180 = \((11\times M - 60\times4)\over2\)

    180 = 11M/2 - 120 

    300 = 11M/2

    600 = 11M

    M = 54(6/11)

    Therefore, the time will be 54(6/11) minute past to 4

    Hence, the correct answer is 54(6/11) minute past to 4

  • Question 9
    5 / -1
    Nitin correctly remembers that Nidhi's birthday is before Friday but after Tuesday. Deepak correctly remembers that Nidhi's birthday is after Wednesday but before Saturday. On which of the following day does Nidhi's birthday definitely fall ?
    Solution

    The logic followed is:

    According to Nitin's memory, Nidhi's birthday is either on Wednesday or Thursday.

    According to Deepak's memory, Nidhi's birthday is either on Thursday or Friday.

    The only common day is Thursday.

    Hence, the correct answer is "Thursday".

  • Question 10
    5 / -1
    Today is Saturday, after 43 days it will be?
    Solution

    Today is Saturday.

    Each day of the week is repeated after every 7 days.

    Hence, after 42 days it will be Saturday.

    So after 43 days, it will be Sunday.

    So the answer is option C
Self Studies
User
Question Analysis
  • Correct -

  • Wrong -

  • Skipped -

My Perfomance
  • Score

    -

    out of -
  • Rank

    -

    out of -
Re-Attempt Weekly Quiz Competition
Self Studies Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Self Studies
Click on Allow to receive notifications
Allow Notification
Self Studies
Self Studies Self Studies
To enable notifications follow this 2 steps:
  • First Click on Secure Icon Self Studies
  • Second click on the toggle icon
Allow Notification
Get latest Exam Updates & FREE Study Material Alerts!
Self Studies ×
Open Now