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Numerical Ability Test - 32

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Numerical Ability Test - 32
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  • Question 1
    5 / -1

    The given data is of the age of the patients in a hospital. What is the mean age of all the patients taken together?

    Solution

    Given:

    Formula used:

    Mean = (∑fixi) / N

    where fi = frequency of ith term

    Xi = ith term

    N = total observations

    Calculations:

    Mean = (∑fixi)/N

    ⇒ Mean = 661/27

    ⇒ Mean = 24.48

    ∴ The mean age of all patients is 24.48 years.

  • Question 2
    5 / -1

    The marks of nine students in ascending order of a test are given below with median 32, then find the value of k.

    12, 16, k, 28, 32, 35, 39, 47, 53

    Solution

    Since, 12, 16, k, 28, 32, 35, 39, 47, 53 are in ascending order

    So, the value of k must be in between 16 to 28

    ∴ The value of k is 27 from option

  • Question 3
    5 / -1

    The following represents age distribution of students in an elementary class. Find the mode of the values:

    8, 7, 9, 14, 10, 6, 13, 8, 11, 7, 19, 12, 11, 7, 8, 10, 11, 14, 8, 10.

    Solution

    GIVEN:

    Data: 8, 7, 9, 14, 10, 6, 13, 8, 11, 7, 19, 12, 11, 7, 8, 10, 11, 14, 8, 10.

    CONCEPT:

    The mode is the number that appears most frequently in a data set.

    CALCULATION:

    Simply find the most recurring number:

    8, 7, 9, 14, 10, 6, 13, 8, 11, 7, 19, 12, 11, 7, 8, 10, 11, 14, 8, 10

    The most occurring number is 8 (4 times)

    ∴ Mode = 8

  • Question 4
    5 / -1

    If Mean is 21, Median is 19. Find Mode.

    Solution

    Given:

    Mean = 21

    Median = 19

    Formula used:

    Mean – Mode = 3(Mean – Median)

    Calculation:

    ⇒ 21 – Mode = 3(21 – 19)

    ⇒ 21 – Mode = 3 × 2

    ⇒ 21 – Mode = 6

    ⇒ 21 – 6 = Mode

    ⇒ 15 = Mode

    ∴ The Mode is 15

  • Question 5
    5 / -1

    In a survey conducted by a group of students on 20 households in a local area, the following frequency tables have been found related to the number of household family members:

    Find the mode of this data.

    Solution

    GIVEN:

    Lower limit of modal class = 3

    Highest Number of families = 9

    Class interval = h = 2

    Frequency of modal class = f1 = 9

    Frequency of class before modal class = f= 7

    Frequency of class after modal class = f2 = 2

    FORMULAE USED:

    Mode = L + (f1 - f0) × h/(2f1 - f0 - f2)

    CALCULATION:

    Mode = 3 + (9 - 7) × 2/(18 - 7 - 2)

    Mode = 3 + (4/9) = 3 + 0.444

    ∴ The mode of this data is 3.444

  • Question 6
    5 / -1

    What is the median of the following fractional numbers:

    Solution

    Given:

    The following fractional numbers: 7/9, 13/16, 2/3, 21/25, 17/21

    Formula used:

    The median formula of a given set of numbers, say having 'n' odd number of observations, can be expressed as:

    Median = [(n + 1)/2]th term

    The median formula of a given set of numbers say having 'n' even number of observations, can be expressed as:
    Median = [(n/2)th term + ((n/2) + 1)th term]/2

    Calculation:

    7/9 = 0.77

    13/16 = 0.81

    2/3 = 0.66

    21/25 = 0.84

    17/21 = 0.80

    Let,s arrange the series from smaller to greater numbers,

    2/3, 7/9, 17/21, 13/16, 21/25

    Here, n = 5 (odd)

    Therefore, the middle term is 17/21.

    ∴​ The median of the following fractional numbers is 17/21

  • Question 7
    5 / -1

    Given below is the data set of runs scored by Rohit Sharma in a tournament : 77, 5, 55, 29, 78, 27, 21, 19, 50, 19, 87, 33, 35, 75, 41

    What is the range of the data?

    Solution

    Given:

    77, 5, 55, 29, 78, 27, 21, 19, 50, 19, 87, 33, 35, 75, 41

    Concept used:

    The range of a given data is the difference between the highest term of the data and the lowest term of the data

    Calculations:

    Given data = (77, 5, 55, 29, 78, 27, 21, 19, 50, 19, 87, 33, 35, 75, 41)

    Highest term of the data = 87

    Lowest term of the data = 5

    Range = 87 - 5

    ⇒ 82

    ∴ The range of the given data is 82

  • Question 8
    5 / -1

    The median of the observations 11, 12, 14, 18, x + 2, 22, 22, 25 and 61, arranged in ascending order, is 21. Then, value of 3x + 7 is:

    Solution

    Concept used:

    The median is the middle value of a data set.

    Calculation:

    According to the given dataset, x + 2 is the middle value which is the median,

    So, x + 2 = 21

    ⇒ x = 19

    Then, the value of 3x + 7 = (3 × 19 + 7) = 64

    ∴ The correct answer is 64

  • Question 9
    5 / -1

    Find the mean deviation about the mean of the distribution:

    Solution

    Given:

    Concept used:

    Calculation:

    So, mean = 433/20

    ⇒ 21.65

    Now,

    To find the mean deviation we have to construct another table

  • Question 10
    5 / -1

    Calculate the mode from the following data.

    Solution

    Formula used:

    Mode is the value that appears most frequently in a data set.

    Calculation:

    The mode is the value with the highest frequency.

    So, highest frequency (number of patients) = 7

    Days of confinement with the highest frequency = 8

    Thus, Mode = 8

    ∴ The correct answer is option (1).

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