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Electromagnetic Waves & Spectrum Test - 5

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Electromagnetic Waves & Spectrum Test - 5
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  • Question 1
    1 / -0.25

     

    The intensity of a plane electromagnetic wave is proportional to

     

    Solution

     

     

    Long distance radio broadcasts use shortwave bands because only these bands can be refracted by the ionosphere.

     

     

  • Question 2
    1 / -0.25

     

    According to Maxwell ’s equations

     

    Solution

     

     

    Maxwell ’s Fourth Equation
    It is based on Ampere ’s circuital law. To understand Maxwell ’s fourth equation it is crucial to understand Ampere ’s circuital law,
    Consider a wire of current-carrying conductor with the current I, since there is an electric field there has to be a magnetic field vector around it. Ampere ’s circuit law states that “The closed line integral of magnetic field vector is always equal to the total amount of scalar electric field enclosed within the path of any shape ”which means the current flowing along the wire(which is a scalar quantity) is equal to the magnetic field vector (which is a vector quantity)

     

     

  • Question 3
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    The direction of propagation of an electromagnetic plane wave is

     

    Solution

     

     

    The direction of propagation of the electromagnetic wave is always perpendicular to the plane in which
    So, the direction of the propagation of the wave, 
    Hence, option B is the correct answer.

     

     

  • Question 4
    1 / -0.25

     

    Infrared waves are produced by

     

    Solution

     

     

    Infrared waves are emitted by hot bodies. They are produced due to the de-excitation of atoms.
    They are called Heat waves as they produce heat falling on matter. This is because water molecules present in most materials readily absorb infrared waves. After absorption, their thermal motion increases, that is, they heat up and heat their surroundings.
    Uses: Infra red lamps; play an important role in maintaining warmth through greenhouse effect.

     

     

  • Question 5
    1 / -0.25

     

    Use the formula  λm  T = 0.29 cmK to obtain the characteristic temperature range for  λm =5 ×10-7 m

     

    Solution

     

     

    A body at temperature T produces a continuous spectrum of wavelengths. For a black body, the wavelength corresponding to maximum intensity of radiation is given according to Planck 's law by the relation, m=0.29cmK/T. For m=106m,T=2900K.Temperatures for other wavelengths can be found. These numbers tell us the temperature ranges required for obtaining radiations in different parts of the electromagnetic spectrum. Thus, to obtain visible radiation, say  =5 ×107m, the source should have a temperature of about 6000K. A lower temperature will also produce this wavelength but not the maximum intensity.

     

     

  • Question 6
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    Optical and radio telescopes are built on the ground, but X-ray Astronomy is possible only from satellites orbiting the earth because

     

    Solution

     

     

    X-rays are absorbed by the atmosphere and therefore the source of X-rays must lie outside the atmosphere to carry out X-ray astronomy and therefore satellites orbiting the earth are necessary but radio waves and visible light can penetrate through the atmosphere and therefore optical and radio telescopes can be built on the ground.

     

     

  • Question 7
    1 / -0.25

     

    Plane electromagnetic waves are

     

    Solution

     

     

    E is the electric field vector, and B is the magnetic field vector of the EM wave. For electromagnetic waves E and B are always perpendicular to each other and perpendicular to the direction of propagation. Electromagnetic waves are transverse waves. The wave number is k = 2 π/λ, where λis the wavelength of the wave.

     

     

  • Question 8
    1 / -0.25

     

    Without the concept of displacement current it is not possible to correctly apply Ampere ’s law on a path parallel to the plates of parallel plate capacitor C in

     

    Solution

     

     

    Explanation:


    Region between the plates:
    - The region between the plates of the capacitor is where the concept of displacement current is most crucial.
    - Without displacement current, the changing electric field between the plates would not be taken into account, leading to significant errors in the calculation of the magnetic field in this region.
    - Displacement current ensures that Ampere 's law is correctly applied in this region, considering both the current in the circuit and the changing electric field between the plates.
     

     

     

  • Question 9
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    Visible range of electromagnetic spectrum is

     

    Solution

     

     

    The visible light spectrum is the segment of the electromagnetic spectrum that the human eye can view. More simply, this range of wavelengths is called visible light. Typically, the human eye can detect wavelengths from 380 to 700 nanometers.
    Option C is the closest so the answer is option C.
     

     

     

  • Question 10
    1 / -0.25

     

    State the part of the electromagnetic spectrum to which 21 cm (wavelength emitted by atomic hydrogen in interstellar space).belongs

     

    Solution

     

     

    Radio waves have wavelengths of 1mm to 100km. Hence, 21cm lies at short wavelength end of radio waves.

     

     

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