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Ray Optics and Optical Instruments Test - 3

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Ray Optics and Optical Instruments Test - 3
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  • Question 1
    1 / -0.25

     

    A Plano convex lens of curvature of 30 cm &R.I. 1.5, produces a real image of an object kept 90cm from it. The magnification is

     

    Solution

     

     

    We have, (1/v)−(1/−90)=1/f ⇒(1.5 −1)(1/30)=1/60
    ∴v=180 cm
    ∴|m|=∣v/u ∣=180/90=2.0

     

     

  • Question 2
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    How will the image formed by a convex lens be affected if the central portion of the lens is wrapped in a black paper

     

  • Question 3
    1 / -0.25

     

    An object is placed at a distance of 10 cm from a co-axial combination of two lenses A and B in contact. The combination forms a real image three times the size of the object. If lens B is concave with a focal length of 30 cm, what is the nature and focal length of lens A ?

     

    Solution

     

     

     

     

  • Question 4
    1 / -0.25

     

    A converging lens is used to form an image on a screen. When the upper half of the lens is covered by an opaque screen

     

    Solution

     

     

    The only difference in covering any part of a lens is that the intensity of the image will reduce. Since the focal length is a function of curvature of the surfaces of the lens and covering a part does not change it, the image will be formed as usual.

     

     

  • Question 5
    1 / -0.25

     

    Total internal reflection can take place only if light is travelling from

     

  • Question 6
    1 / -0.25

     

    An equi-convex thin lens (μ =1.5) of focal length in air as 30cm is sealed into an opening in one end of tank filled with water ((μ =1.33). At the end of the tank opposite the lens is a plane mirror, 80 cm distant from the lens. The position of the image formed by the lens-water-mirror system of a small object outside the tank on the lens axis and 90cm to the left of the lens will be

     

  • Question 7
    1 / -0.25

     

    Optical fibre communication uses the principle of

     

  • Question 8
    1 / -0.25

     

    According to Cartesian sign convention.

     

  • Question 9
    1 / -0.25

     

    When an astronomical telescope is focused on a distant star, the distance of the eye piece from the objective is 60 cm. When focused on a distant flag post the eye piece must be drawn at 0.1cm. If the focal length of the eye piece is 5cm; what will be the distance of the pole from the objective? Assume that the eye is focused for infinity?

     

  • Question 10
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    The objective of a telescope has a focal length of 1.2 m. It is used to view a 10.0 m tall tower 2 km away. What is the height of the image of the tower formed by the objective?

     

    Solution

     

     

    α(Radian)=10/2000=1/200rad
    α=h/F=h/1.2
    h= αx 1.2
    h=(1/200) x1.2 cm
    =6mm

     

     

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