Electric Current and Ohm's law Test

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Electric Current and Ohm's law Test - 3

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Question 1
1 / -0.25

In a potentiometer experiment, for measuring internal resistance of a cell, the balance point has been obtained on the fourth wire. The balance point can be shifted to fifth wire by

A
increasing the current due to auxiliary battery

B
Putting a shunt resistance in parallel with the cell.

C
decreasing the current due to auxiliary battery

D
putting a suitable resistance in series with the cell.

Solution

If the current due to the auxillary battery is decreased, the potential gradient will be decreases, so the balancing length increases.Thus null point will move to fifth wire.
Question 2
1 / -0.25

Meter Bridge is used to

A
determine unknown voltage v

B
determine unknown resistance R

C
determine unknown power P

D
determine unknown emf e

Solution

With a known resistance in one of the gaps, the meter bridge is used to determine the value of unknown resistance by the formula.
Question 3
1 / -0.25

According to Kirchhoff ’s Junction Rule

A
At any junction of circuit elements, the sum of currents entering and leaving the junction must be negative.

B
At any junction of circuit elements, the sum of currents entering and leaving the junction must be positive.

C
At any junction of circuit elements, sum of some of the currents entering the junction may be positive or negative.

D
At any junction of circuit elements, the sum of currents entering the junction must equal the sum of currents leaving it.

Solution

Kirchhoff ’s junction rule is based on the principle of conservation of charge. For steady currents, there can be no accumulation of charge in a junction. The currents entering a junction bring charge to the junction and the currents leaving a junction carry away the charge brought to the junction.
Question 4
1 / -0.25

Ammeter is always used

A
to simulate the element through which current is to be determined

B
in series with the element through which current is to be determined

C
to simulate the element across which voltage is to be determined

D
in parallel with the element through which current is to be determined

Solution

Ammeter is a device used to measure current. Since it has to allow the complete current flowing in the circuit through it, it has to be connected in series. For this reason, ammeters have very low values of resistances so that they do not add to the value of resistance connected in the circuit.
Question 5
1 / -0.25

The sensitivity of the potentiometer can be increased by:

A
increasing the length of potentiometer wire.

B
increasing the e.m.f. of primary cell.

C
decreasing the length of potentiometer wire.

D
increasing the potential gradient.
Solution
A potentiometer is considered to be sensitive if the potential gradient dV/dl is low.

Such a potentiometer can measure very small changes in potential difference.

Increasing the length of the potentiometer wire decreases the potential gradient. Its sensitivity increases. Increasing potential gradient decreases the sensitivity.

Increasing the emf of the primary cell and by decreasing the length, potential gradient increases.
Question 6
1 / -0.25

Direction of the conventional current

A
is the direction in which no charges move

B
is the direction in which positive charges move

C
is the direction in which negative charges move

D
to the direction in which positive charges move

Solution

Current flows in a conductor due to the flow of negatively charged electrons. However, the direction of conventional current is taken to be opposite to the direction of flow of electrons. It can therefore be considered as the direction in which positive charges move.
Question 7
1 / -0.25

Kirchhoff ’s second law is a consequence of

A
Law of conservation of charge

B
Law of conservation of energy

C
Law of conservation of momentum

D
Law of conservation of angular momentum

Solution

Kirchhoff 's second law, also known as the Kirchhoff 's voltage law (KVL) states that the sum of all voltages around a closed loop in any circuit must be equal to zero. This again is a consequence of conservation of energy.
Question 8
1 / -0.25

A battery is connected with a potentiometer wire. The internal resistance of the battery is negligible. If the length of the potentiometer wire of the same material and radius is doubled then

A
Potential gradient does not change

B
Potential gradient becomes half

C
None of these

D
Potential gradient becomes two times

Solution

Potential gradient Is given by V/l. If V and l are constant, the potential gradient also remains constant. The change in the radius will cause a change in the current. This does not change the potential gradient.
Question 9
1 / -0.25

In a meter bridge experiment a balance point is obtained at a distance of 60 cm from the left end when unknown resistance R is in a left gap and 8 ohms resistor is connected in the right gap. When the position of R and 8 ohm resistor is interchanged the balance point will be at distance of

A
40 cm

B
30 cm

C
50 cm

D
60 cm

Solution

60/40 = l/100-l, = R/8

so R=12

now changed position 8 is proportional to l and 12 to (100-l)

8/12 = l/100-l

l = 40ohm
Question 10
1 / -0.25

A Wheatstone bridge is balanced for four resistors R1, R2, R3 and R4 with a Lech lanche cell between A and C and a galvanometer between B and D. The positions of the cell and the galvanometer are interchanged. The balance will

A
Not change

B
Change and can be obtained by changing R1

C
decrease by about 9%9%

D
Change and can be obtained by changing R4

Solution

The balance point will not change . For balancing of wheatstone bridge four arms of resistors are responsible. Interchange the position of galvanometer and cell does not affect balancing of wheatstone bridge.

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Electric Current and Ohm's law Test - 3

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Electric Current and Ohm's law Test - 3

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Question 1

increasing the current due to auxiliary battery

Putting a shunt resistance in parallel with the cell.

decreasing the current due to auxiliary battery

putting a suitable resistance in series with the cell.

Solution

Question 2

determine unknown voltage v

determine unknown resistance R

determine unknown power P

determine unknown emf e

Solution

Question 3

At any junction of circuit elements, the sum of currents entering and leaving the junction must be negative.

At any junction of circuit elements, the sum of currents entering and leaving the junction must be positive.

At any junction of circuit elements, sum of some of the currents entering the junction may be positive or negative.

At any junction of circuit elements, the sum of currents entering the junction must equal the sum of currents leaving it.

Solution

Question 4

to simulate the element through which current is to be determined

in series with the element through which current is to be determined

to simulate the element across which voltage is to be determined

in parallel with the element through which current is to be determined

Solution

Question 5

increasing the length of potentiometer wire.

increasing the e.m.f. of primary cell.

decreasing the length of potentiometer wire.

increasing the potential gradient.

Solution

Question 6

is the direction in which no charges move

is the direction in which positive charges move

is the direction in which negative charges move

to the direction in which positive charges move

Solution

Question 7

Law of conservation of charge

Law of conservation of energy

Law of conservation of momentum

Law of conservation of angular momentum

Solution

Question 8

Potential gradient does not change

Potential gradient becomes half

None of these

Potential gradient becomes two times

Solution

Question 9

40 cm

30 cm

50 cm

60 cm

Solution

Question 10

Not change

Change and can be obtained by changing R1

decrease by about 9%9%

Change and can be obtained by changing R4

Solution

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