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Analog Electronics Test 1

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Analog Electronics Test 1
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  • Question 1
    2 / -0.33
    Given for a FET, gm = 190 mA/v, total capacitance = 1000 PF and voltage gain of -60. The bandwidth(in MHz) will be____
    Solution

    We known that

    \(\frac{{{g_m}}}{C} = Av \times B.W\)

    \(\frac{{190 \times {{10}^{ - 3}}}}{{1000 \times {{10}^{ - 12}}}} = 60 \times B.W\)

    B.W = 3.167 MHz

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