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Network Theory Test 7

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Network Theory Test 7
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  • Question 1
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    The short-circuit admittance matrix of a two-port network is

    \(\left[ {\begin{array}{*{20}{c}} 0&{ - \frac{1}{2}}\\ {\frac{1}{2}}&0 \end{array}} \right]\)

    The two-port network is

    Solution

    Concept:

    Two Port Parameters

    Condition for Symmetry

    Condition for Reciprocal

    Z Parameters

    Z11 = Z22

    Z12 = Z21

    Y parameters

    Y11 = Y22

    Y12 = Y21

    ABCD parameters

    A = D

    AD - BC =1

    H parameters

    h11h22 - h12h21 = 1

    h12 = -h21

    Application:

    For the given network, Y12 ≠ Y21. So the given network is non-reciprocal.

    Y11 = Y22, so the given network is symmetric.

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