Quantitative Aptitude Test

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Quantitative Aptitude Test - 5

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Weekly Quiz Competition

Question 1

1 / -0.25

Directions For Questions

Directions: Go through the given table and solve the question based on it.

Product of Major Crops (tonnes)
	Y1	Y2	Y3	Y4	Y5
Foodgrain (Kharif)	69	78	99	102	111
Foodgrain (Total)	108	130	176	197	217
Cereals (Kharif)	65	74	94	98	106
Cereals (Total)	97	119	162	186	203
Pulses (Kharif)	4	4	5	4	5
Pulses (Total)	12	11	14	11	14
Rice (Kharif)	40	50	66	73	80
Rice (Total)	42	54	74	85	93
Oilseeds (Kharif)	7	5	10	12	14
Oilseeds (Total)	10	9	19	18	24

Total foodgrain production = production of rabi foodgrain + production of kharif foodgrain

...view full instructions

From Y2 to Y5, for which crop was the percentage increase in the rabi crop production the highest?

Rice

Pulses

Cereals

Oilseeds

Solution

Again, do not try to actually calculate. For foodgrains and cereals, the production has approximately doubled from Y2 to Y5.
For pulses it is much less, so pulses are out of consideration.
For oilseeds it's 2.5 times, whereas for rice it is more than 3 times.
Thus, the percentage increase has to be the highest for rice.

Hence, the correct option is (a).

Question 2

1 / -0.25

Directions For Questions

Directions: Go through the given table and solve the question based on it.

Product of Major Crops (tonnes)
	Y1	Y2	Y3	Y4	Y5
Foodgrain (Kharif)	69	78	99	102	111
Foodgrain (Total)	108	130	176	197	217
Cereals (Kharif)	65	74	94	98	106
Cereals (Total)	97	119	162	186	203
Pulses (Kharif)	4	4	5	4	5
Pulses (Total)	12	11	14	11	14
Rice (Kharif)	40	50	66	73	80
Rice (Total)	42	54	74	85	93
Oilseeds (Kharif)	7	5	10	12	14
Oilseeds (Total)	10	9	19	18	24

Total foodgrain production = production of rabi foodgrain + production of kharif foodgrain

...view full instructions

What was the average production of rabi cereals from Y1 to Y5?

20 tonnes

32 tonnes

45 tonnes

66 tonnes

Solution

The average production of rabi cereals from Y1 to Y5 are:-
Required average = $\frac{(32 + 45 + 68 + 88 + 97)}{5}$ = $\frac{330}{5}$ = 66.

Hence, the correct option is (d).

Question 3

1 / -0.25

Directions For Questions

Directions: Go through the given table and solve the question based on it.

Product of Major Crops (tonnes)
	Y1	Y2	Y3	Y4	Y5
Foodgrain (Kharif)	69	78	99	102	111
Foodgrain (Total)	108	130	176	197	217
Cereals (Kharif)	65	74	94	98	106
Cereals (Total)	97	119	162	186	203
Pulses (Kharif)	4	4	5	4	5
Pulses (Total)	12	11	14	11	14
Rice (Kharif)	40	50	66	73	80
Rice (Total)	42	54	74	85	93
Oilseeds (Kharif)	7	5	10	12	14
Oilseeds (Total)	10	9	19	18	24

Total foodgrain production = production of rabi foodgrain + production of kharif foodgrain

...view full instructions

From Y3 to Y4, what was the percentage increase in the total rabi production of the five major crops?

21.64%

42.45%

48.82%

52.56%

Solution

Total rabi production in Y3 = 171
Total rabi production in Y4 = 208
Therefore, percentage increase = $\frac{(208 - 171)}{171}$ x 100 = 21.64%.

Hence, the correct option is (a).

Question 4
1 / -0.25

If $\log _{10} 2=0.3010$, the value of $\log _{10} 80$ is:

A
$16020$

B
$19030$

C
$39030$

D
None of these

Solution

$\log _{10} 80$

$=\log _{10}(8 \times 10)$

$=\log _{10} 8+\log _{10} 10$

$=\log _{10}\left(2^{3}\right)+1$

$=3 \log _{10} 2+1$

$=(3 \times 0.3010)+1$

$=1.9030$
Question 5
1 / -0.25

Directions For Questions

Directions: The graph below shows the number of visitors (in 000s) to 3 different museums of a city in four months.

Go through the given graph and solve the questions based on it.

...view full instructions

By what percentage is the total number of visitors to NMNH more than that visiting IFACS in the given four months?

A
10%

B
15%

C
20%

D
25%

Solution

Total NMNH visitors=15000 ;
Total IFACS visitors=12000;
Reqd. %= ( $\frac{3}{12}$ )100=25%;.

Hence, the correct option is (d).
Question 6
1 / -0.25

Directions For Questions

Directions: The graph below shows the number of visitors (in 000s) to 3 different museums of a city in four months.

Go through the given graph and solve the questions based on it.

...view full instructions

Due to the festive season, the number of visitors to NMNH, NGMA and IFACS increase by 5%, 10% and 5% respectively in October. What is the overall percentage increase in the number of visitors to the three museums in October?

A
5.8%

B
6.0%

C
6.1%

D
6.3%

Solution

Increase in no. of visitors=4000(0.05)+2000(0.1)+3000(0.05)=550;
% increase=( $\frac{550}{9000}$ ) 100=6.1%;

Hence, the correct option is (c).
Question 7
1 / -0.25

The entry fees per head to IFACS is 40% more than that to NMNH. In September, the total collection from the entry fees to NGMA was Rs 26,000 more than that to NMNH. If the total collection from the entry fees from the three museums was Rs 60,000 in September, how much money was collected from entry fees to IFACS in that month?

A
Rs 10,000

B
Rs 14,000

C
Rs 16,400

D
Rs 16,800

Solution

Suppose entry fees for NGMA, NMNH & IFACS are x, y and 1.4y, respectively.
Given: 4000x – 2000y = 26000 which can be simplified to 2x – y = 13…….(i)
Also,4000x + 2000y +2000 x 1.4y = 60000 which can be simplified to 5x + 6y = 75…….(ii)
Solving (i) & (ii), we get
x = 9 and y = 5
So, entry fees collected from IFACS in Sep = 2000 x 7 = Rs. 14000.

Hence, the correct option is (b).
Question 8
1 / -0.25

In the given figure, O is centre of the larger circle of radius 10 cm while P is the centre of the smaller circle. If AB = 10√2 cm, find the area of segment ABC lying outside the smaller circle.

A
22.5π – 25

B
22.5π – 50

C
45π – 50

D
45π – 50

Solution
Question 9
1 / -0.25

If (XY)²= PQX, where each letter represents a distinct digit, then find P + Q.

A
5

B
6

C
7

D
9

Solution

It will help if you remember your squares here.
Since the result is a 3 digit number, the maximum value for XY can be 31 since 312 = 961 and 322 = 1024.
Now, you need to check for each number from 11 to 31 and find the number whose first digit is the same as the last digit of its square (as given in the questions).
The only such number is 19 (192 = 361)
Thus, P = 3; Q = 6 and X = 1 And P + Q = 3 + 6 = 9.

Hence, the correct option is (d).
Question 10
1 / -0.25

Sanya, Babli and Jhanvi started a new business. Sanya's capital was invested for a period which was equal to four times Jhanvi's period of investment, whereas Sanya and Babli invested for the same period. Also, twice Sanya's investment is equal to Jhanvi's investment, and Babli's investment is equal to $\frac{1}{2}$ of Sanya's investment. If the total year-end profit from this business yielded Rs 4,40,000, then what was the total share of Sanya and Babli in this profit?

A
Rs 2,40,000

B
Rs 2,50,000

C
Rs 2,55,000

D
Rs 3,30,000

Solution

Let Sanya and Babli invested for 12 months
Therefore, Jhanvi invested for $\frac{12}{4}$ = 3 months
Let Sanya's investment be 100
Therefore, Jhanvi's investment = 100 x 2 = 200
And, Babli's investment = 0.5 x 100 = 50
Therefore, their total contribution is: Sanya = 100 x 12 = 1200
Jhanvi = 200 x 3 = 600 Babli = 50 x 12 = 600
Thus, the ratio of Sanya:Jhanvi:Babli = 1200:600:600 = 2:1:1
Therefore, the share of Sanya and Babli in profit = $\frac{3}{4}$ x 440000 = 330000.

Hence, the correct option is (d).

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Re-Attempt Weekly Quiz Competition

Quantitative Aptitude Test - 5

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Quantitative Aptitude Test - 5

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SHARING IS CARING

Question 1

Rice

Pulses

Cereals

Oilseeds

Solution

Question 2

20 tonnes

32 tonnes

45 tonnes

66 tonnes

Solution

Question 3

21.64%

42.45%

48.82%

52.56%

Solution

Question 4

\(16020\)

\(19030\)

\(39030\)

None of these

Solution

Question 5

10%

15%

20%

25%

Solution

Question 6

5.8%

6.0%

6.1%

6.3%

Solution

Question 7

Rs 10,000

Rs 14,000

Rs 16,400

Rs 16,800

Solution

Question 8

22.5π – 25

22.5π – 50

45π – 50

45π – 50

Solution

Question 9

5

6

7

9

Solution

Question 10

Rs 2,40,000

Rs 2,50,000

Rs 2,55,000

Rs 3,30,000

Solution

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