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Chemistry Test-8

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Chemistry Test-8
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  • Question 1
    4 / -1

    What is the structural formula of Haloalkane?

    Solution

    The structural formula of Haloalkane is R-X.

    • It was derived from alkanes containing a halogens or more.
    • They are used as flame retardants, fire extinguishers, refrigerants, propellants, solvents, and medicinal items.
    • "RX" in which R is an alkyl or alkyl substituted group and X is a halogen (F, Cl, Br, I).
    • Haloalkanes are commonly used in organic synthesis as synthonous alternatives to alkyl cation (R+).
  • Question 2
    4 / -1

    Which of the following is not a homologous series?

    Solution

    C4H9 is not a homologous series.

    Homologous series:

    • ​Homologous series is a series of compounds with similar chemical properties and some functional groups differing from the successive member by CH2.
    • Carbon chains of varying length have been observed in organic compounds having the same general formula.
    • Alkanes with general formula CnH2n+2, alkenes with general formula CnH2n and alkynes with general formula CnH2n-2 form the most basic homologous series in organic chemistry.
  • Question 3
    4 / -1

    Which of the following elements has the unique ability to form bonds with other atoms of the same element giving rise to large molecules?

    Solution

    Carbon has the unique ability to form bonds with other atoms of the same element giving rise to large molecules.

    • ​The elements in the periodic table show certain properties owing to their nature and size.
    • Catenation is the unique ability of an element to form bonds with other atoms of the same element giving rise to large molecules.
    • Carbon is the only element that shows the property of catenation to a very high extent.
    • Owing to its small size, carbon can form long carbon-carbon chains with stable bonds.
    • The tetravalency of carbon allows it to bond to four other atoms simultaneously. This tendency helps carbon in the forming branched and ring structures.

  • Question 4
    4 / -1

    Which of the following salts are used in photography?

    Solution

    AgCl, AgBr and AgI are used in photography.

    Silver halides are used in black and white photography.

    A photographic film is coated with silver halide. When light falls on the surface, the exposed part of the film is darkened from which photograph is developed. That’s why it is used in photography.

    The salts are reduced to the metal form when light falls on them.

    • \(\mathrm{AgCl}+\mathrm{hv} \rightarrow \mathrm{Ag}^{+}+\mathrm{Cl}+1\) electron
    • \(\mathrm{Ag}^{+}+1 \mathrm{e}^{-} \rightarrow \mathrm{Ag}\)

    When silver metal is formed, it forms a dark image on the film.

    When we take a picture, the camera lens projects a small but accurate image on the surface of this light-sensitive layer, and the silver bromide is decomposed more or less, depending on the intensity of the light received in various points of the image.

    So, silver halides for its unusual sensitivity to light are used in photography.

  • Question 5
    4 / -1

    Why is Glycerol added to soap?

    Solution

    Glycerol is a chemical compound, generally nontoxic, sweet-tasting viscous liquid with the chemical formula C3H8O3.

    • It possesses the property of humectant - a substance that attracts water.
    • It can draw in moisture, preventing drying of the skin.
    • Hence, Glycerol is added to soap to prevent rapid drying.
    • Soaps used for cleaning purposes are sodium or potassium salts of long-chain fatty acids, e.g., stearic, oleic, and palmitic acids.
    • Soaps containing sodium salts are formed by heating fat (i.e., glyceryl ester of fatty acid) with aqueous sodium hydroxide solution.
    • This reaction is known as Saponification.
  • Question 6
    4 / -1

    In the air, N2 and Ooccur naturally but they do not react to form oxides of nitrogen because:

    Solution
    Atomic nitrogen and atomic oxygen don't exist under "normal" conditions because each forms molecules N2 and O2. N2 is less reactive than O2 in most gaseous reactions because there is a strong triple bond between the atoms, all the valence electrons are in bonding orbitals, and more energy is needed to excite them. Therefore, the reaction is endothermic.
  • Question 7
    4 / -1

    The molecule shown below is first treated with BH3 and then treated by basic hydrogen peroxide. The commercially important product so formed is:


    Solution

    The above mentioned reagents are used for conducting hydroboration-oxidation. Hydroboration oxidation follows the following mechanism(For Propene):

    From the figure, it is evident that the product is propan-1-ol. The hydroboration-oxidation mechanism produces anti-Markonikoff addition of water molecules across the double bond.

  • Question 8
    4 / -1

    The oxidation of toluene to benzaldehyde by chromyl chloride is called:

    Solution

    The oxidation of toluene to benzaldehyde by chromyl chloride is called Etard reaction.

    Etard Reaction: The reaction begins with an alkene – allylic hydrogen reaction with chromyl chloride, forming a precipitate called the Etard complex. This Etard complex is then decomposed with the help of a reducing environment to prevent its oxidation into a carboxylic acid. This reducing environment is generally provided by a saturated solution of aqueous sodium sulphite. Carbon tetrachloride is the most commonly used solvent for this method but carbon disulfide and chloroform can also be used as solvents. Aldehyde product of high purity can be obtained by purifying the Etard complex before its decomposition (so that its reaction with the unreacted reagent is prevented). The time frame for this equation may vary from a few days to several weeks but the yields are relatively high.

    Hence, the correct option is (A).
  • Question 9
    4 / -1

    Which of the following colligative property is preferred for the determination of molar masses of solutes in solution?

    Solution

    Osmosis: The net spontaneous flow of the solvent molecules from the solvent to the solution or from a less concentrated solution to a more concentrated solution through a semi-permeable membrane is called osmosis.

    Osmotic pressure: The external pressure that must be applied to the solution side to stop the passage of solvent into the solution through a semi-permeable membrane is known as osmotic pressure.

    The osmotic pressure method has the advantage over other method as pressure measurement is around the room temperature and molarity of the solution is used instead of molarity. As compare to other colligative properties, its magnitude is large even for every dilute solution. Therefore molar mass can be determined by it.

    The figure shows a simple osmotic cell. Both compartments contain water, but the one on the left also contains a solute whose molecules (represented by blue circles) are too large to pass through the membrane. Many artificial and natural substances are capable of acting as semi-permeable membranes. The walls of most plant and animal cells fall into this category.

  • Question 10
    4 / -1

    Which of the following substances is used in black and white photography?

    Solution

    Silver Bromide is used in black and white photography.

    A photographic film is coated with silver bromide. when light falls on the surface, the exposed part of the film is darkened from which photograph is developed. That’s why it is used in photography.

    When we take a picture, the camera lens projects a small but accurate image on the surface of this light-sensitive layer, and the silver bromide is decomposed more or less, depending on the intensity of the light received in various points of the image.

    Silver bromide (AgBr), a soft, pale-yellow, water-insoluble salt well known (along with other silver halides) for its unusual sensitivity to light.

  • Question 11
    4 / -1

    Which of the following Aldehydes is also known as formalin?

    Solution

    Formaldehyde is also known as formalin.

    It is an organic compound which occurs naturally with formula CH2O (H−CHO).

    It is an effective precursor for many other chemicals and compounds.

    This is primarily used in industrial resin processing, e.g. for particle boards and coatings.

    Acetaldehyde and Acrolein are the Aldehydes while Acetone is the Ketones.

  • Question 12
    4 / -1

    Which of the following is the decreasing order of oxidizing power of halogens?

    Solution

    Halogens have a strong tendency to accept electrons.

    Halogens accept electrons from other metals and become uni negative.

    The other substance is oxidized.

    The substances that accept electrons from others are termed as oxidizing agents. Thus, halogens act as good oxidizing agents.

    The oxidizing powers of halogens are measured in terms of their electrode potentials.

    The electrode potentials of halogens decrease in the order:

    \(\mathrm{F}_{2}(+2.87 \mathrm{~V})>\mathrm{Cl}_{2}(+1.36 \mathrm{~V})>\mathrm{Br}_{2}(+1.09 \mathrm{~V})>\mathrm{I}_{2}(+0.54 \mathrm{~V})\)

    Higher electrode potential means a stronger oxidizing agent.

    Thus, the decreasing order of oxidizing power of halogens is F > Cl > Br > I.

  • Question 13
    4 / -1

    Give the general electronic configuration valence shell of 'd' block elements.

    Solution

    Transition elements are those elements whose two outermost shells are incomplete.

    These elements have partially filled d-subshell in the ground state or any of their common oxidation state and are commonly referred to as d-block transition elements.

    The generalized electronic configuration of these elements is (n-1) d1–10 ns1–2.

    The d-block elements are categorized as 1st series transition elements, 2nd series transition elements, 3rd series transition elements and 4th series transition elements.

    The examples are: Cu, Zn, Ag, Cd, Au, Hg, etc.

  • Question 14
    4 / -1

    The electron energy in hydrogen atom is given by \({E}_{n}=-21 \cdot 7 \times 10^{-12} / {n}^{2}\) erg. Calculate the energy required to remove an electron completely from the \({n}=2\) orbit. What is the longest wave length (in \({cm}\) ) of light that can be used to cause this transition?

    Solution

    The required transition is \(n_{1}=2\) to \(n_{2}=\infty\) and corresponding transition energy is:

    \(\Delta E=21.7 \times 10^{-12}\left(\frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}}\right) \mathrm{erg}\)

    \(=\frac{21.7}{4} \times 10^{-12} \mathrm{erg}\)

    \(=5.425 \times 10^{-12} \mathrm{erg}\)

    The longest wavelength that can cause the above transition can be determined as:

    \(\lambda=\frac{h c}{\Delta E}=\frac{6.625 \times 10^{-34} \times 3 \times 10^{8}}{5.425 \times 10^{-12} \times 10^{-7}}\)

    \(=3.66 \times 10^{-7} \mathrm{~m}=3.6 \times 10^{-5} \mathrm{~cm}\)

    Bohr proposed an idea of stationary orbits in which electron revolves. According to Bohr's electron does not lose energy as long as it stays in a stationary orbit. When an electron jumps to lower stationary orbit, energy is lost in the form of electromagnetic radiation. Conversely, when energy is supplied, the electron jumps to a higher stationary orbit.

  • Question 15
    4 / -1

    Naphthalene balls disappear with time because of _______.

    Solution

    Sublimation is a change in a state of matter, just like melting, freezing, and evaporation. Through sublimation, a substance changes from a solid to a gas without ever passing through a liquid phase.

    Example: Dry ice, solid CO2, Naphthalene.

    Evaporation: Evaporation is the process by which water changes from a liquid to a gas or vapor.

    Distillation: Distillation is the process of separating components of a mixture based on different boiling points. Examples of uses of distillation include

    • purification of alcohol desalination
    • crude oil refining
    • making liquefied gases from the air

    Crystallization: Crystallization is the process by which solid forms, where the atoms or molecules are highly organized into a structure known as a crystal.

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