Electrochemistry Test

Result

Electrochemistry Test - 27

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Weekly Quiz Competition

Question 1
4 / -1

The relationship between stardard reduction potential of a cell and equilibrium constant is shown by

A

B

C

D

Solution
Question 2
4 / -1

What will be the emf for the given cell Pt|H₂(P₁)| H⁺ (aq) |H₂(P₂)| Pt

A

B

C

D
none of these

Solution
Question 3
4 / -1

Which of the following reaction is possible at anode ?

A

B

C

D
none of these
Question 4
4 / -1

The resistance of 1 N solution of acetic acid is 250 ohm, when measured in a cell of cell constant 1.15 cm^-1. The equivalent conductance (in ohm^-1 cm² equiv^-1) of 1 N acetic acid is

A
4.6

B
9.2

C
18.4

D
0.023

Solution
Question 5
4 / -1

If 0.01M solution of an electrolyte has a resistance of 40 ohms in a cell having a cell constant of 0.4 cm^-1 then its molar conductance in ohm^-1 cm² mol^-1 will be

A
10⁴

B
10³

C
10²

D
10

Solution
Question 6
4 / -1

The specific conductivity of N/10 KCl solution at 20^oC is 0.0212 ohm^-1 cm^-1 and the resistance of the cell containing this solution at 20^oC is 55 ohm.The cell constant is

A
4.616 cm^-1

B
1.166 cm^-1

C
2.173 cm^-1

D
3.324 cm^-1

Solution
Question 7
4 / -1

The resistance of 0.01N solution of an electrolyte AB at 328 K is 100 ohm. The specific conductance of solution is (cell constant = 1 cm^-1)

A
100 ohm

B
10^-2 ohm^–1

C
10^-2 ohm^-1 cm^-1

D
10² ohm -cm

Solution
Question 8
4 / -1

What weight of copper will be deposited by passing 2 faradays of electricity through a cupric salt (At. wt. of Cu= 63.5)?

A
2.0 g

B
3.175g

C
63.5g

D
127.0g

Solution
Question 9
4 / -1

2.5 faraday of electricity is passed through a solution of CuSO₄.The number of gram equivalent of copper deposited on the cathode will be

A
1

B
2

C
2.5

D
1.25
Question 10
4 / -1

A solution of CuSO₄ is electrolysed for 7 minutes with a current of 0.6 ampere. The amount of electricity passed is equal to

A
4.2 columbs

B
2.6 × 10^-3 Faraday

C
126 Coulombs

D
35 Coulombs