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Solutions Test - 21

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Solutions Test - 21
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  • Question 1
    4 / -1
    A solution of sucrose (molar mass = 342 g/mol) is prepared by dissolving 68.4 g of it per litre of solution, what is its osmotic pressure
    (R = 0.082 L atm K-1 mol-1) at 273 K ?
    Solution

  • Question 2
    4 / -1
    In a 0.2 molal aqueous solution of a weak acid HX, the degree of ionisation is 0.3. Taking Kf for water as 1.85, the freezing point of the solution will be nearest to
  • Question 3
    4 / -1
    At temperature 327°C and concentration C osmotic pressure of a solution is p, the same solutions at concentration C /2 and a temperature 427°C shows osmotic pressure 2 atm, value of p will be
    Solution

  • Question 4
    4 / -1
    18 g of glucose ( C6H12O6 ) is added to 178.2 g of water. The vapour pressure of water for this aqueous solution at 100°C is
  • Question 5
    4 / -1
    The vapour pressure will be lowest for
  • Question 6
    4 / -1
    Osmotic pressure of 0.4% urea solution is 1.64 atm and that of 3.42% cane sugar is 2.46 atm. When the above two solutions are mixed, the osmotic pressure of the resulting solution is
  • Question 7
    4 / -1
    Depression in freezing point is 6 K for NaCl solution if Kf for water is 1.86 K/Kg/mol, amount of NaCl dissolved in 1 Kg water is
  • Question 8
    4 / -1
    If a solution containing 0.072 g atom of sulphur in 100 g of a solvent ( Kf = 7.0 ) gave a freezing point depression of 0.84°C , the molecular formula of sulphur in the solution is
  • Question 9
    4 / -1
    Equimolar solution in the same solvent have
  • Question 10
    4 / -1
    The molar freezing point constant for water is 1.86°C/mol. If 342 g of cane sugar ( C12 H22 O11) is dissolved in 1000 g of water , the solution will freeze at
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