Thermodynamics Test

Result

Thermodynamics Test - 58

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Weekly Quiz Competition

Question 1
4 / -1

Which expression is correct for the work done in adiabatic reversible expansion of an ideal gas

A

B

C

D
Question 2
4 / -1

Calculate ∆G^o for a reaction having standard free energy change of NO₂, NO and O₃ as 12.39 20.72 and 39.06 Kcal/mole

A
47.39

B
47.38

C
4.739

D
–4.739
Question 3
4 / -1

The equilibrium concentration of the species in the reaction A + B = C + D are 3, 5, 10 and 15 mole L^–1 respectively at the for the reaction is

A
13.81

B
–1381.8

C
–138.18

D
1391.6

Solution
Question 4
4 / -1

The standard Gibbs free energy change ∆G^o is related to equilibrium constant K_{P as}

A

B

C

D
Question 5
4 / -1

In the reaction for the transition of carbon in the diamond from to carbon in the graphite from, ∆H is –453.5 cal. This points out that

A
Graphite is chemically different from diamond

B
Graphite is as stable as diamond

C
Graphite is more stable than diamond

D
Diamond is more stable than graphite
Question 6
4 / -1

Which of the following is correct ?

A
1 cal > 1 erg > 1 joule

B
1 erg > 1 cal > 1 joule

C
1 cal > 1 joule > 1 erg

D
1 joule > 1 cal > 1 erg
Question 7
4 / -1

When two moles of water is boiled at 100^o C temperature which gets converted to vapour same temperature. Then what will be change in entropy of system ?

A
25.12

B
52.12

C
21.76

D
217.6

Solution
Question 8
4 / -1

Heat of vapourisation of benzene is 7350 calorie K^–1 mol^–1. Calculate the change in entropy to convert 1 mole gaseous benzene to liquid benzene at 77^o C

A
21 calories K^–1 mol^–1

B
–21 calorie K^–1 mol^–1

C
–21 calorie K^–1

D
21 Calorie K^–1
Question 9
4 / -1

What is the value of G^o at 25^oC for the reaction having equilibrium constant 4.0?
C₂H₅OH + CH₃COOHCH₃COOC₂H₅ + H₂O

A
–82.11

B
+ 82.11

C
+ 821.1

D
–821.1

Solution
Question 10
4 / -1

Standard cell potential of electro chemical cell is 1.20 volt for given reaction. Calculate change in free energy in KJ associated with it

A
115.8

B
–115.8

C
–231.6

D
231.6

Solution