Straight Line and Pair of Straight Lines Test

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Straight Line and Pair of Straight Lines Test - 55

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Weekly Quiz Competition

Question 1
4 / -1

If the line 2x + 3y = 5 and y = mx + c be parallel, then

A

B

C

D
None of these
Question 2
4 / -1

The line (3x – y + 5) + λ(2x – 3y – 4) = 0 will be parallel to y-axis, if λ =

A

B

C

D

Solution
Question 3
4 / -1

The equations of the lines which cuts off an intercept –1 from y-axis and equally inclined to the axes are

A
x – y + 1 = 0, x + y + 1 = 0

B
x – y – 1 = 0, x + y – 1 = 0

C
x – y – 1 = 0, x + y + 1 = 0

D
None of these

Solution
Question 4
4 / -1

A line L is perpendicular to the line 5x – y = 1 and the area of the triangle formed by the line L and coordinate axes is 5. The equation of the line L is

A
x + 5y = 5

B

C
x – 5y = 5

D

Solution
Question 5
4 / -1

If the coordinates of the points A,B,C,D be (a,b), (a\', b\'), (–a, b) and (a\', –b\') respectively, then the equation of the line bisecting the line segments AB and CD is

A
2a'y – 2 bx = ab – a'b'

B
2ay – 2b'x = ab – a'b'

C
2ay – 2 b'x = a'b – ab'

D
None of the above

Solution
Question 6
4 / -1

If the coordinates of A and B be (1,1) and (5,7), then the equation of the perpendicular bisector of the line segment AB is

A
2x + 3y = 18

B
2x – 3y + 18 = 0

C
2x + 3y – 1 = 0

D
3x – 2y + 1 = 0

Solution
Question 7
4 / -1

If the coordinates of the points A, B, C be (–1, 5), (0,0) and (2,2) respectively and D be the middle point of BC, then the equation of the perpendicular drawn from B to the line AD is

A
x + 2y = 0

B
2x + y = 0

C
x – 2y = 0

D
2x – y = 0

Solution
Question 8
4 / -1

The equation of the line passing through the point (x\' , y\') and perpendicular to the line yy\' = 2a(x + x\') is

A
xy' + 2ay + 2ay' – x' y' = 0

B
xy' + 2ay – 2ay' – x' y' = 0

C
xy' + 2ay + 2ay' + x' y' = 0

D
xy' + 2ay – 2ay' + x' y' = 0

Solution
Question 9
4 / -1

If the middle points of the sides, BC, CA and AB of the triangle ABC be (1,3), (5,7) and (–5,7) respectively then the equation of the side AB is

A
x – y – 2 = 0

B
x – y + 12 = 0

C
x + y – 12 = 0

D
None of these

Solution
Question 10
4 / -1

If the coordinates of the vertices of the triangle ABC be (–1, 6), (–3, –9), and (5, –8) respectively, then the equation of the median through C is

A
13x – 14y – 47 = 0

B
13x – 14y + 47 = 0

C
13x + 14y + 47 = 0

D
13x + 14y – 47 = 0

Solution