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Parabola Test - 5

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Parabola Test - 5
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  • Question 1
    1 / -0

    If the normal at a point P on a parabola passes through its focus, then P is

    Solution

    Equation of a normal to the parabola y2 = 4ax is y = mx – 2am – am3. It passes through the focus (a, 0) if m = 0 and the point P(0, 0) is the vertex.

     

  • Question 2
    1 / -0

    Let L be a normal to the parabola y2 = 4x. If L passes through the point (9, 6), then L is not given by

    Solution

    The equation of normal to the parabola y2 = 4ax in slope form is y = mx - 2am - am3.

    So, the equation of normal to the parabola y2 = 4x is y = mx – 2m – m3.

    As it passes through (9, 6), we get

    6 = 9m – 2m – m3

    ⇒ m3 – 7m + 6 = 0

    ⇒ m = 1, 2, –3

    This shows that L is not given by option (3).

     

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