Chemistry Test 162

Result

Chemistry Test 162

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Weekly Quiz Competition

Question 1
4 / -1

Radius of 3^rd orbit of Li²⁺ ion is x cm then de Broglie wavelength of electrons in the first orbit is (in cm)

A
6πx

B
2πx / 9

C
2πx / 3

D
8πx / 3

Solution
Question 2
4 / -1

An aqueous solution of 6.3 g oxalic acid dihydrate is made up to 250 mL. The volume of 0.1 N NaOH required to completely neutralize 10 ml of this solution is

A
40 mL

B
20 mL

C
10 mL

D
4 mL

Solution
Question 3
4 / -1

What will be the heat of formation of methane, if the heat of combustion of carbon is ‘–x’ kJ, heat of formation if water is ‘–y’ kJ and heat of combustion of methane is ‘–z’ kJ

A
(– x – y + z)

B
(– z – x + 2y) kJ

C
(– x – 2y – z) kJ

D
(– x – 2y + z)

Solution
Question 4
4 / -1

The pH of 0.1 molar solution of the acid HQ is 3. The value of the ionisation constant K_a of the acid is

A
3 × 10^–1

B
1 × 10^–3

C
1 × 10^–5

D
1 × 10^–7

Solution
Question 5
4 / -1

Which of the following statement about hydrogen are correct

(a) Hydrogen has three isotopes of which tritium is radioactive in nature

(b) Hydrogen never acts as a cation in ionic salt

(c) Hydrogen ion, H⁺, does not exist free in solution

(d) Hydrogen does not act as an oxidising agent

A
(a) and (d)

B
(c) and (d)

C
(a), (b) and (c)

D
(b), (c) and (d)

Solution

Hydrogen can get reduced so it can be have as oxidising agent.
Question 6
4 / -1

The pollutants which come directly in the air from sources are called primary pollutants. Primary pollutants are sometimes converted into secondary pollutants. Which of the following belongs to secondary air pollutants?

A
CO

B
Hydrocarbon

C
Peroxyacetyl nitrate

D
NO

Solution

Primary pollutants are directly emitted from fossil fuels, and also factories, These includes oxides of sulphur, carbon, methane. When the primary pollutants react with other components present in the atmosphere, secondary pollutants are formed. Smog, Peroxyacetyl nitrate are the examples of secondary air pollutants.
Question 7
4 / -1

Which of the statements about solutions of electrolytes is not correct?

A
Conductivity of solution depends upon size of ions.

B
Conductivity depends upon viscosity of solution.

C
Conductivity does not depend upon solvation of ions present in solution.

D
Conductivity of solution increases with temperature.

Solution

Higher the solvation of ions, slower will be their movement

∴ Conductivity depends on solvation
Question 8
4 / -1

Which of the following process is not responsible for the presence of electric charge on the sol particles?

A
Electron capture by sol particles

B
Adsorption of ionic species from solution

C
Formation of Helmholtz electrical double layer

D
Absorption of ionic species from solution

Solution

Adsorption of ions from solution is responsible and not the absorption.
Question 9
4 / -1

Among following which are amphoteric oxide?

Mn₂O₇, CrO₃, Cr₂O₃, CrO, V₂O₅, V₂O₄

A
V₂O₅, Cr₂O₃

B
Mn₂O₇, CrO₃

C
CrO, V₂O₅

D
V₂O₅, V₂O₄

Solution

V₂O₅ and Cr₂O₃ are amphoteric oxides.

V₂O₄ and CrO are Basic oxides.

Mn₂O₇ and CrO₃ are Acidic oxides.
Question 10
4 / -1

Which of the following reactions does not occur in Bessemer converter in the extraction of copper from chalcopyrites?

A

B
FeO + SiO₂ → FeSiO₃

C

D
Cu₂S + 2Cu₂O → 6Cu + SO₂

Solution

During besbezerisation slag is formed and self reduction takes place.

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Re-Attempt Weekly Quiz Competition

Chemistry Test 162

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Chemistry Test 162

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SHARING IS CARING

Question 1

6πx

2πx / 9

2πx / 3

8πx / 3

Solution

Question 2

40 mL

20 mL

10 mL

4 mL

Solution

Question 3

(– x – y + z)

(– z – x + 2y) kJ

(– x – 2y – z) kJ

(– x – 2y + z)

Solution

Question 4

3 × 10–1

1 × 10–3

1 × 10–5

1 × 10–7

Solution

Question 5

(a) and (d)

(c) and (d)

(a), (b) and (c)

(b), (c) and (d)

Solution

Question 6

CO

Hydrocarbon

Peroxyacetyl nitrate

NO

Solution

Question 7

Conductivity of solution depends upon size of ions.

Conductivity depends upon viscosity of solution.

Conductivity does not depend upon solvation of ions present in solution.

Conductivity of solution increases with temperature.

Solution

Question 8

Electron capture by sol particles

Adsorption of ionic species from solution

Formation of Helmholtz electrical double layer

Absorption of ionic species from solution

Solution

Question 9

V2O5, Cr2O3

Mn2O7, CrO3

CrO, V2O5

V2O5, V2O4

Solution

Question 10

FeO + SiO2 → FeSiO3

Cu2S + 2Cu2O → 6Cu + SO2

Solution

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3 × 10^–1

1 × 10^–3

1 × 10^–5

1 × 10^–7

V₂O₅, Cr₂O₃

Mn₂O₇, CrO₃

CrO, V₂O₅

V₂O₅, V₂O₄

FeO + SiO₂ → FeSiO₃

Cu₂S + 2Cu₂O → 6Cu + SO₂