Chemistry Test 281

Result

Chemistry Test 281

Score
-
out of -
Rank
-
out of -

TIME Taken - -

Weekly Quiz Competition

Question 1
4 / -1

What is the name of the following compound?

CH₃CH₂COCI

A
Butanoyl chloride

B
Propanoyl chloride

C
1 chloro propanone

D
None of these

Solution

It consists of three carbon atoms in the parent chain and chloroformyl group (-COCI)

In the IUPAC name, the suffix "oyl chloride" is added. Therefore, the IUPAC name will be propanoyl chloride.
Question 2
4 / -1

Identify the product for the following reaction.

CH ≡ CH + HOCI →

A
CH CI₂ – C H O

B
CH(OH) = CHCl

C
CICH₂CH₂OH

D
CH₃COCI

Solution

HOCI → OH^- + CI⁺

CI+ shall attack acetylene as an electrophile and OH^- will end the addition with a nucleophilic addition. Therefore, the final reaction will be:
Question 3
4 / -1

Which of the following names is correct for

A
3- Formaldehyde-1,3-dial

B
2, 3, 4- Triformylpropane

C
2-Formylmethylbutane-1, 4-dial

D
Propane-1, 2, 3-tricarbaldehyde

Solution

Since there are three carbon atoms in long chain and it contains 3 -CHO groups (one on each carbon atom).

IUPAC suffix "aldehyde" will added due to presence of functional group -CHO.

Therefore, the correct IUPAC name will be propane-1, 2, 3-tricarbaldehyde.
Question 4
4 / -1

Propanal on treatment with dilute sodium hydroxide gives:

A
CH₃CH₂CH₂CH₂CH₂CHO

B
CH₃CH₂CH(OH)CH₂CH₂CHO

C
CH₃CH₂CH(OH)CH (CH₃)CHO

D
CH₃CH₂COOH

Solution

An alpha (α) hydrogen is the hydrogen which is bonded to alpha carbon. Alpha carbon is the first carbon which is bonded to the functional group. As propanal contains alpha hydrogen, it undergoes self aldol condensation to give beta hydroxy (aldol) compound. The reaction is as follows:
Question 5
4 / -1

Which of the following organic compounds does not undergo diazotisation?

A
m-toluidine

B
Aniline

C
p-aminophenol

D
Benzylamine

Solution

Benzylamine, on reaction with nitrous acid, gives unstable diazonium salt which in turn gives alcohol with a gas, that is nitrogen as shown below:
Question 6
4 / -1

The coupling of diazonium salt of 4-amino benzene sulphonic acid with N, N-dimethyl benzamine produces

A
Phenolphthalein

B
Methyl red

C
Methyl orange

D
Litmus

Solution

The coupling of diazonium salt of 4-aminobenzene sulphonic acid with N, N-dimethyl benzamine produces methyl orange.
Question 7
4 / -1

Which among the following statements is incorrect?

A
Primary amines show intermolecular hydrogen bonding.

B
Secondary amines show intermolecular hydrogen bonding.

C
Tertiary amines show intermolecular hydrogen bonding.

D
Amines have lower boiling point as compared to alcohols and carboxylic acids of comparable molar mass.

Solution

Tertiary amines do not have any hydrogen atom attached directly to the nitrogen and hence, do not exhibit hydrogen bonding. Hence, the option (c) is incorrect.
Question 8
4 / -1

Which of the following compounds give carbylamine reaction?

A
CH₃CONH₂

B
CH₃NH₂

C
(CH3)₂NH

D
CH₃COOH

Solution

The carbylamine reaction (also known as the Hoffmann Isocyanide Synthesis) is the synthesis of an isocyanide by the reaction of a primary amine, chloroform, and base.

CH₃NH₂+ 3KOH + CHCl₃ →CH₃NC + 3KCl + 3H₂O
Question 9
4 / -1

Which of the following indicates open chain structure of glucose?

A
Penta-acetyl derivative of glucose

B
Cyanohydrin formation with HCN

C
Reaction with Fehling solution

D
Reaction with Tollen's reagent

Solution

Pentacetyl formation of glucose indicates that the latter contain 5–OH groups, indicating the open chain structure of glucose.
Question 10
4 / -1

The numbers of stereo centres present in linear and cyclic structures of glucose are respectively:

A
4 and 4

B
4 and 5

C
5 and 4

D
5 and 5

Solution

The number of stereo centres in the linear structure of glucose is 4 and in the cyclic structure is 5.