Self Studies
Self Studies
Self Studies
Self Studies
Selfstudy
Selfstudy

Chemistry Test 37

Result Self Studies

Chemistry Test 37
  • Score

    -

    out of -
  • Rank

    -

    out of -
TIME Taken - -
Self Studies

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Self Studies Self Studies
Weekly Quiz Competition
  • Question 1
    4 / -1

    Iron exhibits + 2 and +3 oxidation states. Which of the following statements about iron is incorrect?

    Solution

    FeO → More basic, more ionic, less volatile 
    Hence, option D is correct.

  • Question 2
    4 / -1

    Calomel (Hg2Cl2) on reaction with ammonium hydroxide gives

    Solution

    Hg2Cl2 + 2NH4OH → Hg + Hg(NH2)Cl + NH4Cl + 2H2O

    Hence, option A is correct.

  • Question 3
    4 / -1

    Standard reduction electrode potentials of three metals A, B and C are +0.5V, –3.0V and –1.2 V respectively. The reducing power of these metals are

    Solution

    More –ve value of Eo means larger reducing power.

    Hence, option A is correct.

  • Question 4
    4 / -1

    In SN2 reactions, the correct order of reactivity for the following compounds : 
    CH3Cl, CH3CH2Cl, (CH3)2CHCl and (CH3)3CCl is :

    Solution

    SN2 reaction follows nucleophilic substitition reaction mechanism .In such reactions, one bond is broken and one bond is formed simultaneously. 

    Rate of SN2 reaction increases when steric crowding decreases. Steric crowding refers to the presence of more bulky group in the surrounding of the  atom. In moving from  CH3Cl to (CH3)3CCl there is an increase in number of CH3 group due to which steric hindrance increases.

    Hence, option D is correct.

  • Question 5
    4 / -1

    Which of the following compounds can be detected by Molisch's test?

    Solution

    Molisch's Test : When a drop or two of alcoholic solution of α-naphthol is added to sugar solution and then concentrated. H2SO4 is added along the sides of test tube, formation of violet ring takes place at the junction of two liquids 
    Hence, option B is correct.

Self Studies
User
Question Analysis

  • Correct -

  • Wrong -

  • Skipped -

My Perfomance
  • Score

    -

    out of -
  • Rank

    -

    out of -
Re-Attempt Weekly Quiz Competition
Self Studies Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Self Studies
Click on Allow to receive notifications
Allow Notification
Self Studies
Self Studies Self Studies
To enable notifications follow this 2 steps:
  • First Click on Secure Icon Self Studies
  • Second click on the toggle icon
Allow Notification
Get latest Exam Updates & FREE Study Material Alerts!
Self Studies ×
Open Now