JEE Advanced Mi...

When 100 ml of 0.1 M NaCN solution is titrated with 0.1 M HCl solution the variation of pH of solution with volume of HCl added will be :

For the reversible reaction N₂(g) + 3H₂(g)  2NH₃(g) at 500°C, the value of Kp is 1.44 × 10^–5 when partial pressure is measured in atm. The corresponding value of Kc, with concentration in mol L^–1 is.

0.1 M solution of KI reacts with excess of H₂SO₄ and KIO₃ solutions, according to equation.

5I^– + IO₃^– + 6H+ →3I₂ + 3H₂O ; which of the following statement is correct

Equal volumes of following solutions are mixed, in which case the pH of resulting solution will be average value of pH of two solutions.

Identify the correct statement (s)

Statement-1 : Solubility of BaSO₄ in 0.1 M Na₂SO₄ is 10^–9 M hence its KSP is 10^–18

Statement-2 : Because for BaSO₄ KSP = (s)² [ symbols have their usual meanings]

Statement-1 : In a container containing gas ‘A’ at temperature 400 K, some more gas A gas at temperature 300 K is introduced. The pressure of the system increases.

Statement-2 : Increase in gaseous particles increases the number of collisions among the molecules, hence the pressure increases

Statement-1 : e/m ratio in case of anode ray experiment is different for different gases.

Statement-2 : The ion of gases formed after the ejection of electron are different if gas is different.

Statement-1 : Graphite can be converted into diamond by application of very high pressure and temperature, using a suitable catalyst.

Statement-2 : Graphite is thermodynamically more stable and less dense than diamond.