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JEE Advanced Mix Test 23

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JEE Advanced Mix Test 23
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Weekly Quiz Competition
  • Question 1
    4 / -1

    When 100 ml of 0.1 M NaCN solution is titrated with 0.1 M HCl solution the variation of pH of solution with volume of HCl added will be :

    Solution

    Initially pH will decrease fast, then slowly due to buffer formation and then will decrease fast as buffer action diminishes.

  • Question 2
    4 / -1

    For the reversible reaction N2(g) + 3H2(g)  2NH3(g) at 500°C, the value of Kp is 1.44 × 10–5 when partial pressure is measured in atm. The corresponding value of Kc, with concentration in mol L–1 is.

    Solution

  • Question 3
    4 / -1

    Solution

  • Question 4
    4 / -1

    0.1 M solution of KI reacts with excess of H2SO4 and KIO3 solutions, according to equation.

    5I– + IO3– + 6H+ →3I2 + 3H2O ; which of the following statement is correct

    Solution

  • Question 5
    4 / -1

    Equal volumes of following solutions are mixed, in which case the pH of resulting solution will be average value of pH of two solutions.

    Solution

    (D) pH = 5 CH3COOH and pH = 9 NH3 (aq), both must be of equal concentrations as pKa = pKb. Hence pH = pOH only if concentrations are equal so on mixing equal volume we will get CH3COONH4 salt solution and its pH is given is given by

  • Question 6
    4 / -1

    Identify the correct statement (s)

    Solution

  • Question 7
    4 / -1

    Statement-1 : Solubility of BaSO4 in 0.1 M Na2SO4 is 10–9 M hence its KSP is 10–18

    Statement-2 : Because for BaSO4 KSP = (s)2 [ symbols have their usual meanings]

    Solution

  • Question 8
    4 / -1

    Statement-1 : In a container containing gas ‘A’ at temperature 400 K, some more gas A gas at temperature 300 K is introduced. The pressure of the system increases.

    Statement-2 : Increase in gaseous particles increases the number of collisions among the molecules, hence the pressure increases

    Solution

  • Question 9
    4 / -1

    Statement-1 : e/m ratio in case of anode ray experiment is different for different gases.

    Statement-2 : The ion of gases formed after the ejection of electron are different if gas is different.

    Solution

    Specific charge depends on mass of ion, which is different for different  gases.

  • Question 10
    4 / -1

    Statement-1 : Graphite can be converted into diamond by application of very high pressure and temperature, using a suitable catalyst.

    Statement-2 : Graphite is thermodynamically more stable and less dense than diamond.

    Solution

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