JEE Advanced Mix Test 73

Result

JEE Advanced Mix Test 73

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Weekly Quiz Competition

Question 1
4 / -1

A small ball thrown with an initial velocity μ directed at an angle θ = 37° above the horizontal collides inelastically (e = 1/4) with a vertical massive wall moving with a uniform horizontal velocity u/5 towards ball. After collision with the wall, the ball returns to the point from where it was thrown. Neglect friction between ball and wall. The time t from beginning of motion of the ball till the moment of its impact with the wall is (tan37° = 3/4)

A
3μ/5g

B
18μ/25g

C
54μ/125g

D
54μ/25g
Question 2
4 / -1

A cube of side l and mass M is placed on rough horizontal surface and the friction is sufficient so that it will not move, if a constant force F = Mg is applied horizontally l/4 above the surface. Then the torque due to normal force about center of the cube is equal to

A
mgl/2

B
mgl/4

C
mgl/8

D
zero
Question 3
4 / -1

A particle of charge q and mass m is projected with a velocity v₀ towards a circular region having uniform magnetic field B perpendicular and into the plane of paper from point P as shown in the figure. R is the radius and O is the centre of the circular region. If the line OP makes an angle θ with the direction of v₀ then the value of v₀ so that particle passes through O is

A

B

C

D
Question 4
4 / -1

A ray of light from a liquid ( μ = √3 ) is incident on a system of two right angled prism of refractive indices √3 and √2 as shown. The ray suffers zero deviation when emerges into air from CD. The angle of incidence i is

A
45⁰

B
35⁰

C
20⁰

D
10⁰
Question 5
4 / -1

The formula of the following chain silicate (pyroxene) can be represented as

A

B

C

D

Solution

It is a chain silicate.
Question 6
4 / -1

is a first order reaction. If A is strong mono protic acid and B is strong diprotic acid and reaction kinetic is studied by using a standard solution of NaOH required toneutralise reaction mixture at different instants of time. When initially we had taken sameconcentration of A in each case.Now it was observer that volume required after 971 sec was double that required initially, then thehalf life of reaction is:

A
485 sec

B
1942 sec

C
3010 sec

D
971 sec

Solution
Question 7
4 / -1

Reduction potentials of some ions are given below. Arrange them in decreasing order of oxidizing power.

A
ClO₄⁻ > IO₄⁻ > BrO₄⁻

B
IO₄⁻ > BrO₄⁻ > ClO₄⁻

C
BrO₄⁻ > IO₄⁻ > ClO₄⁻

D
BrO₄⁻ > ClO₄⁻ > IO₄⁻

Solution

The reduction potential of the substance is the ability of the substance to be reduced.So as the reduction potential increases reducing ability of the substance increases.It means oxidizing power of the substance (The ability of the substance to make the other substance to lose the electrons increases which noting but oxidizing power) increases.

So the decreasing order of oxidizing power is BrO₄⁻ > IO₄⁻ > ClO₄⁻
Question 8
4 / -1

A
1/6

B
1/2

C
2

D
-1/2

Solution

Use expansion of sin^-1 x&tan^-1 x to get the result
Question 9
4 / -1

Area of the region bounded by the curve y=1/x + 1 , the tangent at P (2, 3/2) and the line x = 1 is

A
4/5 ℓn2

B
-5/4 ℓn3

C
-5/4 ℓn2

D
ℓn2 - 5/8

Solution

Plot the curve y - 1 = 1/x and translate the axis to get required area.
Question 10
4 / -1

A

B

C

D

Solution