JEE Main Test 114

Result

JEE Main Test 114

Score
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Rank
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TIME Taken - -

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Weekly Quiz Competition

Question 1
4 / -1

The turn ratio of a transformer is 1 : 2. An electrolytic DC cell of emf 2 V is connected to its primary. The output voltage across transformer is

A
zero

B
4 V

C
2.4 V

D
12 V

Solution

Option (1) is correct, As of transformer works only on AC not DC.
Question 2
4 / -1

A boat is moving due East in a region where the earth's magnetic field is 5.0 × 10^-5 NA^-1 m^-1 due North and horizontal. The boat carries a vertical aerial 2 m long. If the speed of the boat is 1.50 ms^-1 , the magnitude of the induced emf in the wire of aerial is

A
0.75 mV

B
0.50 mV

C
0.15 mV

D
1 mV

Solution
Question 3
4 / -1

The angle between the lines √3x - y - 2 = 0 and x - √3y + 1 = 0 is

A
90^o

B
60^o

C
45^o

D
30^o

Solution
Question 4
4 / -1

A solenoid 60 mm long has 50 turns on it and is wound on an iron rod of 7.5 mm radius. Find the flux through the solenoid when the current in it, is 3A. The relative permeability of iron is 600.

A
1.66 Wb

B
1.66 nWb

C
1.66 mWb

D
1.66 μWb

Solution
Question 5
4 / -1

The electric field of an electromagnetic wave travelling through vacuum is given by the equation E = E₀ sin (kx - ωt). The quantity that is independent of wavelength is

A
k / ω

B
kω

C
ω

D
k²ω

Solution
Question 6
4 / -1

In order to increase the volume of a gas by 10%, the pressure of the gas should be

A
increased by 10%

B
increased by 1%

C
decreased by 10%

D
decreased by 1%

Solution

According to Boyle’s law, p ∝ 1/V , Hence in order to increase the volume of a gas by 10% , the pressure of the gas should be decreased be 10 % .
Question 7
4 / -1

A

B

C

D

Solution
Question 8
4 / -1

If the two circles x² + 2y² - 2x + 22y + 5 = 0 and x² + y² + 14x + 6y + k = 0 intersect orthogonally, then k is equal to

A
47

B
- 47

C
49

D
- 49

Solution
Question 9
4 / -1

A
16/7

B
25/4

C
25/12

D
16/9

Solution
Question 10
4 / -1

Light from two coherent sources of the same amplitude A and wavelength λ, illuminates the screen. The intensity of the central maximum is I₀. If the sources were incoherent, the intensity at the same point will be

A
4I₀

B
2I₀

C
I₀

D
I₀/2

Solution