JEE Main Test 50

Result

JEE Main Test 50

Score
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out of -
Rank
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TIME Taken - -

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Weekly Quiz Competition

Question 1
4 / -1

Angular momentum of a particle rotating with a central force is constant due to

A
constant torque

B
constant force

C
constant linear momentum

D
zero torque

Solution

A central force passes through the axis of rotation, so torque is zero.

If no external torque is acting on a particle, the angular momentum of the particle will be constant.
Question 2
4 / -1

A student measured the length of a rod and wrote it as 3.50 cm. Which instrument did he use to measure it?

A
A screw gauge having 50 divisions in the circular scale and pitch as 1 mm

B
A meter scale

C
A vernier caliper, where the 10 divisions in the vernier scale matches with 9 divisions in the main scale, and the main scale has 10 divisions in 1 cm

D
A screw gauge having 100 divisions in the circular scale and pitch as 1 mm

Solution

Measured value of the length of rod = 3.50 cm

So, least count of the measuring instrument must be 0.01 cm = 0.1 mm.

For a vernier scale,

10 MSD = 1 cm = 10 mm

=> 10 MSD = 1 cm = 10 mm

Also, 9 MSD = 10 VSD

LC = 1 MSD - 1 VSD = (1 - 0.9) mm = 0.1 mm