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Physics Test 255

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Physics Test 255
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  • Question 1
    4 / -1

    A long infinite current-carrying wire is bent in the shape as shown in the figure. The magnetic induction at point O is:

    Solution

    An infinite wire, carrying current, is bent in the following way.

    Two semi-infinite parts and a bent finite part. We have to find the induced magnetic field at an external point o, at a distance R. The corresponding figure is shown below.

    Magnetic field induced by a finite current-carrying conductor

    The magnetic field at a distance R is given by:

    B = (μ I / 4πR) (cos θ₁ - cos θ₂) ........(i)

    where θ₁ and θ₂ are the angles made by the endpoints of the wire to the external point.

    Using the right-hand thumb rule, we determine the direction of the magnetic field.

    For the 1st semi-infinite part:

    Given: θ₁ = 0 and θ₂ = 90° = π/2

    Substituting these values in equation (i), we get:

    B₁ = (μ I / 4πR) 

    For the bent portion:

    Given: θ₁ = 45° and θ₂ = 135°

    The magnetic field is calculated as:

    B₂ = (μ I / 4πR) [ (1/√2) + (1/√2) ] 

    ⇒ B₂ = (μ I / 2√2πR) 

    For the second semi-infinite part:

    Given: θ₁ = π/2 and θ₂ = 0

    The magnetic field is:

    B₃ = (μ I / 4πR) 

    Total Magnetic Field:

    Summing up the individual contributions, the total magnetic field at point O is:

    B = B₁ + B₂ + B₃

    ⇒ B = (μ I / 2√2πR)

     

  • Question 2
    4 / -1

    A particle is projected with a velocity v so that its range on a horizontal plane is twice the greatest height attained If g is acceleration due to gravity, then its range is

    Solution

     

  • Question 3
    4 / -1

    A block of mass 30 kg is suspended by three strings as shown in figure. Find the tension in each string.

    Solution

    Method I: Considering equilibrium of each part of system The whole system is in equilibrium; therefore, for each part 

    From the free-body diagram of block C, T= 300 N.


  • Question 4
    4 / -1

    A block of mass 1 kg is at rest on a horizontal table. The coefficient of static friction between the block and the table is 0.50. If g = 10 ms−2, then the magnitude of a force acting upwads at an angle of 60 from the horizontal that will just start the block moving is:

    Solution

    R + P sin 60 = Mg

    R = Mg − P sin 60°

    Frictional force

    F = μR

    = μ[Mg − Psin60

     

  • Question 5
    4 / -1

    A disc of mass m and radius R placed on a smooth horizontal table as shown in figure. A light ideal string passes through the disc such that the one end of the string is attached to a small body of mass m and the other end is being pulled with a force F. The circumference of the disc is sufficiently rough so that the string does not slip over it. Find acceleration of the small body.

    Solution

  • Question 6
    4 / -1

    A block of wood floats in a liquid with four-fifths of its volume submerged. If the relative density of wood is 0.8, what is the the density of the liquid in units of kgm−3?

    Solution

     

  • Question 7
    4 / -1

    The potential energy of a particle of mass 1 kg.in motion along the x-axis is given by: U = 4(1 − cos2x), where x is in metres. The period of small oscillation (in seconds) is

    Solution

     

  • Question 8
    4 / -1

    A point mass is subjected to two simultaneous sinusoidal displacements in the x-directions: x1(t) = A sin ωt and x2(t) = A sin(ωt + 2π/3). Adding a third sinusoidal displacement x(t) = B sin(ωt + ϕ) brings the mass to a complete rest. The values of B and ϕ are respectively

    Solution

     

  • Question 9
    4 / -1

    A positively charged ball hangs from a long silk thread. Electric field at a certain point (at the same horizontal level of the ball) due to this charge is E. Let us put a positive test charge q0 at this point and measure F/q0 on this charge. Then, E

    Solution

  • Question 10
    4 / -1

    Solution

     

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