Thermodynamics Test

Result

Thermodynamics Test - 54

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Weekly Quiz Competition

Question 1
4 / -1

Work done by 0.1 mole of a gas at 27°C to double its volume at constant pressure is (R = 2 cal mol^–1 ° C^–1)

A
54 cal

B
600 cal

C
60 cal

D
546 cal

Solution
Question 2
4 / -1

Unit mass of a liquid with volume V₁ is completely changed into a gas of volume V₂ at a constant external pressure P and temperature T. If the latent heat of evaporation of the given mass is L, then the increase in the internal energy of the system is

A
zero

B

C

D

Solution
Question 3
4 / -1

A
– 340 kJ

B
– 170 kJ

C
170 kJ

D
340 kJ

Solution
Question 4
4 / -1

An ideal gas have volume V_o at 27°C. It is heated at constant pressure so that its volume becomes 2V_o. The final temperature is

A
54°C

B
32.6°C

C
327°C

D
150 K

Solution
Question 5
4 / -1

Which of the following is correct in terms of increasing work done for the same initial and final state

A
Adiabatic < Isothermal < Isobaric

B
isobaric < Adiabatic < isothermal

C
Adiabatic < Isobaric < Isothermal

D
None of the above

Solution
Question 6
4 / -1

Which of the following is a slow process?

A
Isothermal

B
Adiabatic

C
Isobaric

D
None of these
Question 7
4 / -1

A
28 J

B
27 J

C
25 J

D
24 J

Solution
Question 8
4 / -1

A container having I mole of a gas at a temperature 27°C has a movable piston which maintains at constant pressure in container of I atm. The gas compressed until temperature becomes 127°C. The work done is(C_p for gas is 7.03 cal/mol-K)

A
703 J

B
831 J

C
121 J

D
2035 J

Solution
Question 9
4 / -1

In a reversible isochoric change

A
∆W = 0

B
∆Q = 0

C
∆T = 0

D
∆U = 0

Solution
Question 10
4 / -1

Entropy of a thermodynamic system does not change when this system is used for

A
Conduction of heat from a hot reservoir to a cold reservoir

B
Conversion of heat into work isobarically

C
Conversion of heat into internal energy isochorically

D
Conversion of work into heat isochorically