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Current Electricity Test - 107

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Current Electricity Test - 107
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  • Question 1
    4 / -1
    A voltmeter has a range 0–V with a series resistance R. With a series resistance 2R, the range is 0–V\'. Thecorrect relation between V and V\' is
    Solution

  • Question 2
    4 / -1
    The measurement of voltmeter in the following circuitis

  • Question 3
    4 / -1
    If an ammeter is to be used in place of a voltmeter then we must connect with the ammeter a
  • Question 4
    4 / -1
    A 10 m long wire of 20 Ω resistance is connected with a battery of 3 volt e.m.f. (negligible internal resistance) and a 10 Ω resistance is joined to it is series. Potential gradient along wire in volt per meter is
    Solution

  • Question 5
    4 / -1
    A potentiometer has uniform potential gradient across it. Two cells connected in series (i) to support each other and (ii) to oppose each other are balanced over 6 m and 2 m respectively on the potentiometer wire. The e.m.f.\'s of the cells are in the ratio of
    Solution

  • Question 6
    4 / -1
    The material of wire of potentiometer is
  • Question 7
    4 / -1
    To convert a 800 mV range milli voltmeter of resistance 40 Ω into a galvanometer of 100 mA range, the resistance to be connected as shunt is
    Solution

  • Question 8
    4 / -1
    The potential difference across the 100 Ω resistance in the following circuit is measured by a voltmeter of 900 Ω resistance. The percentage error made in readingthe potential difference is

    Solution

  • Question 9
    4 / -1
    A galvanometer, having a resistance of 50 Ω gives a full scale deflection for a current of 0.05 A. The length in meter of a resistance wire of area of cross-section 2.97 × 10–2cm2 that can be used to convert the galvanometer into an ammeter which can read a maximum of 5 A current is (Specific resistance of the wire = 5 × 10–7 m Ω)
    Solution

  • Question 10
    4 / -1
    Resistance of 100 cm long potentiometer wire is 10 Ω, it is connected to a battery (2 volt) and a resistance R in series. A source of 10 mV gives null point at 40 cmlength, then external resistance R is
    Solution

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