Current Electricity Test

Result

Current Electricity Test - 108

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Weekly Quiz Competition

Question 1
4 / -1

The current flowing in a coil of resistance 90 Ω is to be reduced by 90%. What value of resistance should beconnected in parallel with it

A
9 Ω

B
90 Ω

C
1000 Ω

D
10 Ω

Solution
Question 2
4 / -1

A galvanometer of 50 ohm resistance has 25 divisions. A current of 4 × 10^–4 ampere gives a deflection of onedivision. To convert this galvanometer into a voltmeter having a range of 25 volts, it should be connected witha resistance of

A
2500 Ω as a shunt

B
2450 Ω as a shunt

C
2550 Ω in series

D
2450 Ω in series

Solution
Question 3
4 / -1

A galvanometer of resistance, G, is shunted by a resistance S ohm. To keep the main current in the circuit unchanged, the resistance to be put in serieswith the galvanometer is

A

B

C

D

Solution
Question 4
4 / -1

A milli voltmeter of 25 milli volt range is to be converted into an ammeter of 25 ampere range. The value (in ohm) of necessary shunt will be

A
0.001

B
0.01

C
1

D
0.05

Solution
Question 5
4 / -1

In the circuit shown the cells A and B have negligible resistances. For V_A = 12 V, R₁ = 500 Ω and R = 100 Ω the galvanometer (G) shows no deflection. The value of V_B is

A
4 V

B
2 V

C
12 V

D
6 V

Solution
Question 6
4 / -1

In an electrical cable there is a single wire of radius 9 mm of copper. Its resistance is 5 Ω. The cable is replaced by 6 different insulated copper wires, the radius of each wire is 3 mm. Now the total resistance ofthe cable will be

A
7.5 Ω

B
45 Ω

C
90 Ω

D
270 Ω

Solution
Question 7
4 / -1

In the figure shown, the capacity of the condense C is 2μF. The current in 2 Ω resistor is

A
9 A

B
0.9 A

C

D

Solution
Question 8
4 / -1

When the key K is pressed at time t = 0, which of the following statements about the current I in the resistor AB of the given circuit is true?

A
I = 2 mA at all t

B
I = mA oscillates between 1 mA and 2 mA

C
I =1mA all t

D
At t = 0, / = 2 mA and with time it goes to 1 mA

Solution
Question 9
4 / -1

A torch bulb rated as 4.5 W, 1.5 V is connected as shown in the figure. The e.m.f. of the cell needed to make the bulb glow at full intensity is

A
4.5 V

B
1.5 V

C
2.67 V

D
13.5 V

Solution
Question 10
4 / -1

In the circuit shown, the value of each resistance is r, then equivalent resistance of circuit between points A and B will be

A
(4/3) r

B
3r/2

C
r/3

D
8r/7

Solution