Current Electricity Test

Result

Current Electricity Test - 90

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Weekly Quiz Competition

Question 1
4 / -1

Two resistors are connected (a) in series (b) in parallel. The equivalent resistance in the two cases are 9 ohm and 2 ohm respectively. Then the resistances of the component resistors are

A
2 ohm and 7 ohm

B
3 ohm and 6 ohm

C
3 ohm and 9 ohm

D
5 ohm and 4 ohm

Solution
Question 2
4 / -1

Resistances of 6 ohm each are connected in the manner shown in adjoining figure. With the current 0.5 ampere as shown in figure, the potential difference V_P– V_Q is

A
3.6 V

B
6.0 V

C
3.0 V

D
7.2 V

Solution
Question 3
4 / -1

The equivalent resistance of the arrangement of resistances shown in adjoining figure between the points A and B is

A
6 ohm

B
8 ohm

C
16 ohm

D
24 ohm

Solution
Question 4
4 / -1

In the network of resistors shown in the adjoining figure, the equivalent resistance between A and B is

A
54 ohm

B
18 ohm

C
36 ohm

D
9 ohm

Solution
Question 5
4 / -1

A wire is broken in four equal parts. A packet is formed by keeping the four wires together. The resistance of the packet in comparison to the resistance of the wirewill be

A
Equal

B
One fourth

C
One eight

D
1/16 th

Solution
Question 6
4 / -1

Four resistances are connected in a circuit in the given figure. The electric current flowing through 4 ohm and 6 ohm resistance is respectively

A
2 amp and 4 amp

B
1 amp and 2 amp

C
1 amp and 1 amp

D
2 amp and 2 amp

Solution
Question 7
4 / -1

An infinite sequence of resistances is shown in the figure. The resultant resistance between A and B will be, when R₁ =1 ohm and R₂ = 2 ohm

A
Infinity

B
1 Ω

C
2 Ω

D
1.5 Ω

Solution
Question 8
4 / -1

The equivalent resistance between points A and B with switch S open and closed are respectively

A
4 Ω, 8 Ω

B
8 Ω, 4 Ω

C
6 Ω, 9 Ω

D
9 Ω, 6 Ω

Solution
Question 9
4 / -1

In the figure shown, the total resistance between A and B is

A
12 Ω

B
4 Ω

C
6 Ω

D
8 Ω

Solution
Question 10
4 / -1

The current from the battery in circuit diagram shown is

A
1 A

B
2 A

C
1.5 A

D
3 A

Solution