Electrostatics ...

The capacity of a condenser in which a dielectric of dielectric constant 5 has been used, is C. If the dielectric is replaced by another with dielectric constant 20, the capacity will become

An insulator plate is passed between the plates of a capacitor. Then the displacement current

A charge of 10^–9C is placed on each of the 64 identical drops of radius 2 cm They are then combined to form a bigger drop. Find its potential

The plates of a parallel plate capacitor of capacity 50µC are charged to a potential of 100 volts and then separated from each other so that the distance between them is doubled. How much is the energy spent in doing so?

Two spherical conductors each of capacity C are charged to potentials V and –V. These are then connected by means of a fine wire. The loss of energy will be

The area of the plates of a parallel plate condenser is A and the distance between the plates is 10 mm. There are two dielectric sheets in it, one of dielectric constant 10 and thickness 6 mm and the other of dielectric constant 5 and thickness 4 mm The capacity of the condenser is

An air capacitor of capacity C =10µF is connected to a constant voltage battery of 12V. Now the space between the plates is filled with a liquid of dielectric constant 5. The charge that flows now from battery to the capacitor is

A parallel plate capacitor is first charged and then a dielectric slab is introduced between the plates. The quantity that remains unchanged is

The force between the plates of a parallel plate capacitor of capacitance C and distance of separation of the plates d with a potential difference V between the plates, is

Two metal spheres of capacitance C₁ and C₂ carry some charges. They are put in contact and then separated. The final charges Q₁ and Q₂ on them will satisfy