Electrostatics Test

Result

Electrostatics Test - 119

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Weekly Quiz Competition

Question 1
4 / -1

A parallel plate consider with oil between the plates (dielectric constant of oil K = 2) has a capacitance C. If the oil is removed, then capacitance of the capacitor becomes

A

B
2C

C

D

Solution
Question 2
4 / -1

A parallel plate capacitor has circular plates of 0.08 m radius and 1.0 × 10^–3 m separation. If a P.D. of 100 volt is applied, the charge will be

A
1.8 × 10^–10 C

B
1.8 × 10^–8C

C
1.8 × 10^–20 C

D
None of these

Solution
Question 3
4 / -1

The capacity of a parallel plate condenser is 10 µF without dielectric. Dielectric of constant 2 is used to fill half the distance between the plates, the new capacitance in µF is

A
10

B
20

C
15

D
13.33

Solution
Question 4
4 / -1

The energy stored in the condenser is

A

B

C

D

Solution
Question 5
4 / -1

A battery is used to charge a parallel plate capacitor till the potential difference between the plates becomes equal to the electromotive force of the battery. The ratio of the energy stored in the capacitor and the work done by the battery will be

A
1

B
2

C
1/4

D
1/2

Solution
Question 6
4 / -1

Two identical charged spherical drops each of capacitance C merge to form a single drop. The resultant capacitance is

A
Equal to 2C

B
Greater than 2C

C
Less than 2C but greater than C

D
Less than C

Solution
Question 7
4 / -1

The capacitance of a parallel plates capacitor with air as medium is 3µF. With the introduction of a dielectric medium between the plates, the capacitance becomes 15µF. The permittivity of medium is

A
5

B
15

C
0.44 × 10^–10C²N^–1m^–2

D
8.854 × 10^–11C²N^–1m^–2

Solution
Question 8
4 / -1

The radius of a metallic sphere if its capacitance is1/9F, is

A
10⁶m

B
10⁷m

C
10⁹m

D
10⁸m

Solution
Question 9
4 / -1

The ratio of charge to potential of a body is known as

A
Capacitance

B
Conductance

C
Inductance

D
Resistance
Question 10
4 / -1

If the capacity of a spherical conductor is 1 pico farad then its diameter would be

A
1.8 × 10^–3 m

B
18 × 10^–3 m

C
1.8 × 10^–5 m

D
18 × 10^–7 m

Solution