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Electrostatics Test - 159

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Electrostatics Test - 159
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  • Question 1
    4 / -1
    Two electric charges 12c and –6c are placed 20cm apart in air. There will be a point P on the line joining these charges and outside the region between them, at which the electric potential is zero. The distance of P from –6c charge is ........
    Solution

  • Question 2
    4 / -1

  • Question 3
    4 / -1
    4 Points charges each +q is placed on the circumference of a circle of diameter 2d in such a way that they form a square. The potential at the centre is ......
  • Question 4
    4 / -1
    Three identical charges each of 2c are placed at the vertices of a triangle ABC as shown in the figure. If AB + AC = 12 cm and AB . AC = 32cm2, the potential energy of the charge at A is .....
    Solution

  • Question 5
    4 / -1
    A ball of mass 1 gm and charge 10–8 c moves from a point A, where the potential is 600 volt to the point B where the potential is zero. Velocity of the ball of the point B is 20cm/s. The velocity of the ball at the point A will be .....
    Solution

  • Question 6
    4 / -1
    Three charges Q, +q and +q are placed at the vertices of an equilateral triangle of side l as shown in the figure. It the net electrostatic energy of the system is zero, then Q is equal

    Solution

  • Question 7
    4 / -1

    Solution

  • Question 8
    4 / -1
    A small conducting sphere of radius r is lying concentrically inside a bigger hollow conducting sphere of radius R. The bigger and smaller sphere are charged with Q and q (Q > q) and are insulated from each other. The potential difference between the spheres will be ......
  • Question 9
    4 / -1
    If 3 charges are placed at the vertices of equilateral triangle of charge ‘q’ each. What is the net potential energy, if the side of equilateral triangle is l cm.
    Solution

  • Question 10
    4 / -1
    If identical charges (–q) are placed at each corner of a cube of side b, then electric potential energy of charge (+q) which is placed at centre of the cube will be .....
    Solution

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