Electrostatics Test

Result

Electrostatics Test - 163

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Weekly Quiz Competition

Question 1
4 / -1

Two identical metal plates are given positive charges Q₁ and Q₂ (< Q₁) respectively. If they are now brought close to together to form a parallel plate capacitor with capacitance C, the potential difference between them is

A

B

C

D

Solution
Question 2
4 / -1

A
80, 40, 40 and 20V

B
20, 40, 40 and 80V

C
35, 35, 35 and 35V

D
80, 20, 20 and 20V

Solution
Question 3
4 / -1

In the arrangement of capacitors shown in figure, each capacitor is of 9μF, then the equivalent capacitance between the points A and B is

A
18 F

B
9 F

C
15 F

D
4.5 F

Solution
Question 4
4 / -1

A

B

C

D

Solution
Question 5
4 / -1

Two air capacitors A = 1F , B = 4 F are connected in series with 35 V source. When a medium of dielectric constant K = 3 is introduced between the plates of A, change on the capacitor changes by

A
16 c

B
32 c

C
28 c

D
60 c

Solution
Question 6
4 / -1

A parallel plate capacitor with air between the plates has a capacitance of 9 pF. The separation between its plates is d. The space between the plates is now filled with two dielectrics. One of the dielectric constant K₁ = 3 and thickness d/3 while the other one has dielectric constant K₂ = 6 and thickness 2d/3. Capacitance of the capacitor is now

A
1.8 pF

B
20.25 pF

C
40.5 pF

D
45 pF

Solution
Question 7
4 / -1

A

B

C

D
Question 8
4 / -1

A parallel plate condenser with dielectric of constant K between the plates has a capacity C and is charged to potential V volt. The dielectric slab is slowly removed from between the plates and reinserted. The network done by the system in this process is

A
Zero

B

C

D
Question 9
4 / -1

A

B

C

D
Question 10
4 / -1

A

B

C

D

Solution