Alternating Current Test

Result

Alternating Current Test - 22

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Weekly Quiz Competition

Question 1
4 / -1

A virtual current of 4 A and 50 Hz flows in an ac circuit containing a coil. The power consumed in the coil is 240 W. If the virtual voltage across the coil is 100 V its inductance will be

A

B

C

D

Solution
Question 2
4 / -1

A circuit draws 330 W from a 110 V, 60 Hz ac line. The power factor is 0.6 and the current lags the voltage. The capacitance of a series capacitor that will result in a power factor of unity is equal to

A
31 µF

B
54 µF

C
151 µF

D
201 µF

Solution
Question 3
4 / -1

In the adjoining figure the impedance of the circuit will be

A
120 ohm

B
50 ohm

C
60 ohm

D
90 ohm

Solution
Question 4
4 / -1

The figure shows variation of R, X_L and X_C with frequency f in a series L,C,R circuit. Then for what frequency point, the circuit is inductive

A
A

B
B

C
C

D
All points

Solution
Question 5
4 / -1

When an ac source of e.m.f. e = E₀ sin(100t) is connected across a circuit, the phase difference between the e.m.f. e and the current iin the circuit is observed to be π/4, as shown in the diagram. If the circuit consists possibly only of RC or LC in series, find the relationship between the two elements

A
R = 1 kΩ, C = 10µF

B
R = 1 kΩ, C = 1µF

C
R = 1 kΩ, L = 10H

D
R = 1 kΩ, L = 1H

Solution
Question 6
4 / -1

A bulb and a capacitor are in series with an ac source. On increasing frequency how will glow of the bulb change

A
The glow decreases

B
The glow increases

C
The glow remain the same

D
The bulb quenches

Solution
Question 7
4 / -1

What is the r.m.s. value of an alternating current which when passed through a resistor produces heat which is thrice of that produced by a direct current of 2 amperes in the same resistor

A
6 amp

B
2 amp

C
3.46 amp

D
0.66 amp

Solution
Question 8
4 / -1

A
0.6, 0.06 W

B
0.06, 0.6 W

C
0.6, 4.8 W

D
4.8, 0.6 W

Solution
Question 9
4 / -1

In an LCR circuit R = 100 ohm. When capacitance C is removed, the current lags behind the voltage by π/3. When inductance L is removed, the current leads the voltage by π/3. The impedance of the circuit is

A
50 ohm

B
100 ohm

C
200 ohm

D
400 ohm

Solution
Question 10
4 / -1

A group of electric lamps having a total power rating of 1000 watt is supplied by an ac voltage E = 200 sin(310t + 60° ). Then the r.m.s. value of the circuit current is

A
10A

B
10√2 A

C
20 A

D
20√2 A

Solution