Alternating Current Test

Result

Alternating Current Test - 49

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Weekly Quiz Competition

Question 1
4 / -1

The power factor of a good choke coil is

A
Nearly zero

B
Exactly zero

C
Nearly one

D
Exactly one

Solution
Question 2
4 / -1

An alternating current source of frequency 100 Hz is joined to a combination of a resistance, a capacitance and a coil in series. The potential difference across the coil, the resistance and the capacitor is 46, 8 and 40 volt respectively. The electromotive force of alternating current source in volt is

A
94

B
14

C
10

D
76

Solution
Question 3
4 / -1

A 10 ohm resistance, 5 mH coil and 10 μF capacitor are joined in series. When a suitable frequency alternating current source is joined to this combination, the circuit resonates. If the resistance is halved, the resonance frequency

A
Is halved

B
Is doubled

C
Remains unchanged

D
In quadrupled

Solution
Question 4
4 / -1

In a series circuit R = 300 Ω, L = 0.9 H, C = 2.0µF and ω = 1000 rad/sec. The impedance of the circuit is

A
1300 Ω

B
900 Ω

C
500 Ω

D
400 Ω

Solution
Question 5
4 / -1

A
11.4 Ω, 17.5 A

B
30.7 Ω, 6.5 A

C
40.4 Ω, 5 A

D
50Ω, 4 A

Solution
Question 6
4 / -1

In a series LCR circuit, operated with an ac of angularfrequency ω, the total impedance is

A

B

C

D
Question 7
4 / -1

A

B

C

D
1000 Hz

Solution
Question 8
4 / -1

An e.m.f. E = 4 cos (1000 t) volt is applied to an LR–circuit of inductance 3 mH and resistance 4 ohms. The amplitude of current in the circuit is

A

B
1.0 A

C

D
0.8 A

Solution
Question 9
4 / -1

In an ac circuit, a resistance of R ohm is connected in series with an inductance L. If phase angle between voltage and current be 45°, the value of inductive reactance will be

A

B

C
R

D
Cannot be found with the given data

Solution
Question 10
4 / -1

A coil of inductance L has an inductive reactance of X_Lin an ac circuit in which the effective current is I. The coil is made from a super–conducting material and has no resistance. The rate at which power is dissipated inthe coil is

A
0

B
IX_L

C
I²X_L

D

Solution