Moving Charges and Magnetism Test

Result

Moving Charges and Magnetism Test - 14

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
4 / -1

Electrons move at right angles to a magnetic field of 1.5 × 10^–2 tesla with a speed of 6 × 10⁷ m/s. If the specific charge of the electron is 1.7 × 10¹¹ C/kg, the radius of the circular path will be

A
2.9 cm

B
3.9 cm

C
2.35 cm

D
3 cm

Solution
Question 2
4 / -1

The cyclotron frequency of an electron grating in a magnetic field of 1 T is approximately

A
28 MHz

B
280 MHz

C
2.8 GHz

D
28 GHz

Solution
Question 3
4 / -1

The radius of a circular loop is r and a current i is flowing in it. The equivalent magnetic moment will be

A
ir

B
2πir

C
iπr²

D
1/r²

Solution
Question 4
4 / -1

A current carrying loop is placed in a uniform magnetic field. The torque acting on it does not depend upon

A
Shape of the loop

B
Area of the loop

C
Value of the current

D
Magnetic field
Question 5
4 / -1

To make the field radial in a moving coil galvanometer

A
The number of turns in the coil is increased

B
Magnet is taken in the form of horse-shoe

C
Poles are cylindrically cut

D
Coil is wounded on aluminum frame
Question 6
4 / -1

A current carrying circular loop is freely suspended by a long thread. The plane of the loop will point in the direction

A
Wherever left free

B
North-south

C
East-west

D
At 45° with the east-west direction

Solution
Question 7
4 / -1

A current carrying small loop behaves like a small magnet. If A be its area and M its magnetic moment, the current in the loop will be

A
M/A

B
A/M

C
MA

D
A²M

Solution
Question 8
4 / -1

Which is a vector quantity

A
Density

B
Magnetic flux

C
Intensity of magnetic field

D
Magnetic potential
Question 9
4 / -1

An electron in a circular orbit of radius 0.05 nm performs 10¹⁶ revolutions per second. The magnetic moment due to this rotation of electron is (in A – m² )

A
2.16 × 10^-23

B
3.21 × 10^-22

C
3.21 × 10^-24

D
1.26 × 10^-23

Solution
Question 10
4 / -1

A long conducting wire carrying a current I is bent at 120° (see figure). The magnetic field B at a point P on the right bisector of bending angle at a distance d from the bend is (μ₀ is the permeability of free space)

A

B

C

D

Solution