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Moving Charges and Magnetism Test - 25

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Moving Charges and Magnetism Test - 25
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  • Question 1
    4 / -1
    An electron whose e/m is 1.76 × 1011C/kg enter a region where there is a uniform magnetic field of induction 2 × 10-3 tesla with a velocity of 3 × 106 m/sec in a direction making an angle of 45o with the field. The pitch of its helical path in the region is

    Solution

  • Question 2
    4 / -1
    A candidate connects a moving coil voltmeter V and moving coil ammeter A and resistor R as shown in Fig ?

  • Question 3
    4 / -1
    The magnetic field at the centre of a loop of a circular wire of radius r carrying current I may be taken as B0 .If a particle of charge q moving with speed v passes the centre of semicircular wire, as shown in Fig. along the axis of the wire, the force on it due to the current is

    Solution

  • Question 4
    4 / -1
    Three infinitely long conductors A, B and C carrying currents as shown in the fig. the position of the point lying on the straight line AC where the magnetic field is zero is between

    Solution

  • Question 5
    4 / -1
    What is the magnetic field induction at the centre O of the arc in the Fig.?

    Solution

  • Question 6
    4 / -1
    A conductor AB of length L carrying a current I2, is placed perpendicular to a long straight conductor XY carrying current I1, as shown in Fig. the force on AB is magnitude is

    Solution

  • Question 7
    4 / -1
    A charge +q is moving along positive x – direction From origin it follows trajectory (non circular) as shown in Fig. The electric and magnetic fields existing in the region to the right of y – axis may be

  • Question 8
    4 / -1
    A length L of wire carries a steady current I. It is bent first to form a circular plane coil of one turn. The same length is now bent more sharply to give a double loop of smaller radius. The magnetic field at the centre caused by the same current is
    Solution

  • Question 9
    4 / -1
    If a copper rod carries a direct current, the magnetic field associated with the current will be
  • Question 10
    4 / -1

    Solution

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