Moving Charges and Magnetism Test

Result

Moving Charges and Magnetism Test - 64

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Weekly Quiz Competition

Question 1
4 / -1

An electron is revolving round a proton, producing a magnetic field of 16 weber/m² in a circular orbit of radius 1 Å. It\'s angular velocity will be

A

B

C

D

Solution
Question 2
4 / -1

A square conducting loop of side length L carries a current I. The magnetic field at the centre of the loop is

A
Independent of L

B
Proportional to L²

C
Inversely proportional to L

D
linearly proportional to L

Solution
Question 3
4 / -1

A uniform electric field and a uniform magnetic field are produced, pointing in the same direction. If an electron is projected with its velocity pointing in the same direction

A
The electron will turn to its right

B
The electron will turn to its left

C
The electron velocity will increase in magnitude

D
The electron velocity will decrease in magnitude

Solution
Question 4
4 / -1

Two particles X and Y having equal charges, after being accelerated through the same potential difference, enter a region of uniform magnetic field and describe circular path of radius R₁ and R₂ respectively. The ratio of mass of X to that of Y is

A

B

C

D

Solution
Question 5
4 / -1

A charged particle moving in a magnetic field experiences a resultant force

A
In the direction of field

B
In the direction opposite to the field

C
In the direction perpendicular to both the field and its velocity

D
None of the above

Solution
Question 6
4 / -1

If the direction of the initial velocity of the charged particle is perpendicular to the magnetic field, then the orbit will be
Or
The path executed by a charged particle whose motion is perpendicular to magnetic field is

A
A straight line

B
An ellipse

C
A circle

D
A helix
Question 7
4 / -1

A 2 MeV proton is moving perpendicular to a uniform magnetic field of 2.5 tesla. The force on the proton is

A
3 × 10^–10 N

B
8 × 10^–11 N

C
3 × 10^–11 N

D
8 × 10^–12 N

Solution
Question 8
4 / -1

A
Zero

B
–evB

C

D
None of these
Question 9
4 / -1

A uniform magnetic field B is acting from south to north and is of magnitude 1.5 wb/m². If a proton having mass = 1.7 × 10^–27 kg and charge = 1.6 × 10^–19C moves in this field vertically downwards with energy 5 MeV, then the force acting on it will be

A
7.4 × 10¹² N

B
7.4 × 10^–12 N

C
7.4 × 10¹⁹ N

D
7.4 × 10^–19 N

Solution
Question 10
4 / -1

The magnetic force on a charged particle moving in the field does not work, because

A
Kinetic energy of the charged particle does not change

B
The charge of the particle remains same

C
The magnetic force is parallel to velocity of the particle

D
The magnetic force is parallel to magnetic field

Solution