Magnetism and Matter Test

Result

Magnetism and Matter Test - 39

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Weekly Quiz Competition

Question 1
4 / -1

In a vibration magnetometer, the time period of a bar magnet oscillating in horizontal component of earth\'s magnetic field is 2 sec. When a magnet is brought near and parallel to it, the time period reduces to 1 sec. The ratio H/F of the horizontal component H and the field F due to magnet will be

A
3

B
1/3

C

D

Solution
Question 2
4 / -1

A

B

C

D

Solution
Question 3
4 / -1

Two magnets of equal mass are joined at right angles to each other as shown. Magnet 1 has a magnetic moment 3 times that of magnet 2. This arrangement is pivoted so that it is free to rotate in the horizontal plane. In equilibrium what angle will the magnet 1 subtend with the magnetic meridian

A

B

C

D

Solution
Question 4
4 / -1

A short magnet oscillates with a time period 0.1 s at a place where horizontal magnetic field is 24 µt. A downward current of 18 A is established in a vertical wire 20 cm east of the magnet. The new time period of oscillator

A
0.1 s

B
0.089 s

C
0.076 s

D
0.057 s

Solution
Question 5
4 / -1

Two magnets A and B are identical and these are arranged as shown in the figure. Their length is negligible in comparison to the separation between them. A magnetic needle is placed between the magnets at point P which gets deflected through an angle θ under the influence of magnets. The ratio of distance d₁ and d₂ will be

A
(2 tan θ)^1/3

B
(2 tan θ)^–1/3

C
(2 cot θ)^1/3

D
(2 cot θ)^–1/3

Solution
Question 6
4 / -1

Two short magnet of equal dipole moments M are festened perpendicularly at their centre (figure). The magnitude of the magnetic field at a distance d from the centre on the bisector of the right angle is

A

B

C

D

Solution
Question 7
4 / -1

A small coil C with N = 200 turns is mounted on one end of a balance beam and introduced between the poles of an electromagnet as shown in figure. The cross sectional area of coil is A = 1.0 cm², length of arm OA of the balance beam is l= 30 cm. When there is no current in the coil the balance is in equilibrium. On passing a current l = 22 mA through the coil the equilibrium is restored by putting the additional counter weight of mass ∆m = 60 mg on the balance pan. Find the magnetic induction at the spot where coil is located.

A
0.4 T

B
0.3 T

C
0.2 T

D
0.1 T

Solution
Question 8
4 / -1

Two identical bar magnets with a length 10 cm and weight 50 g-weight are arranged freely with their like poles facing in a inverted vertical glass tube. The upper magnet hangs in the air above the lower one so that the distance between the nearest pole of the magnet is 3 mm. Pole strength of the poles of each magnet will be

A
6.64 amp × m

B
2 amp × m

C
10.25 amp × m

D
None of the above

Solution
Question 9
4 / -1

Let ɸ₁ and ɸ₂ be the angles of dip observed in two vertical planes at right angles to each other and ɸ be the true angle of dip, then

A
cos² ɸ = cos² ɸ₁ + cos² ɸ₂

B
sec² ɸ = sec² ɸ₁ + sec² ɸ₂

C
tan² ɸ = tan² ɸ₁ + tan² ɸ₂

D
cot² ɸ = cot² ɸ₁ + cot² ɸ₂

Solution
Question 10
4 / -1

Each atom of an iron bar (5 cm × 1 cm × 1 cm) has a magnetic moment 1.8 × 10^–23 Am². Knowing that the density of iron is 7.78 × 10³ kg m^–3, atomic weight is 56 and Avogadro\'s number is 6.02 × 10²³ the magnetic moment of bar in the state of magnetic saturation will be

A
4.75 Am²

B
5.74 Am²

C
7.54 Am²

D
75.4 Am²

Solution