Thermal Propert...

The rectangular surface of area 8 cm × 4 cm of a black body at a temperature of 127^oC emits energy at the rate of E per second. If the length and breadth of the surface are each reduced to half of the initial value and the temperature is raised to 327^oC, the rate of emission of energy will become

At temperature T, the power radiated by a body is Q watts. At the temperature 3T the power radiated by it will be

Two spherical black of radii r₁ and r₂ and with surface temperature T₁ and T₂ respectively radiate the same power. Then, the ratio of r₁ and r₂ will be

Temperature of a black body increases from 327^oC to 927^oC, the initial energy possessed is 2 KJ, what is its final energy?

The original temperature of a black body is 727^oC. The temperature at which this black body must be raised so as to double the total radiant energy is

The energy spectrum of a black body exhibits a maximum around a wavelength λ₀. The temperature of the black body is now changed such that the energy is maximum around a wavelength 3λ₀/4. The power radiated by the black body will now increase by a factor of

A black body at a temperature of 127^oC radiates heat at the rate of 1 cal/cm² × sec. At a temperature of 527^oC the rate of heat radiation from the body in (cal/cm² × sec) will be

The spectral energy distribution of star is maximum at twice temperature as that of sun. The total energy radiated by star is

A black body radiates at the rate of W watts at a temperature T. If the temperature of the body is reduced to T/3, it will radiates at the rate of (in Watts)

If the temperature of the sun were to be increased from T to 2T and its radius from R to 2R, then the ratio of the radiant energy received on the earth to what it was previously will be