Electric Forces & Fields Test

Result

Electric Forces & Fields Test - 5

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Weekly Quiz Competition

Question 1
4 / -1

Which of the following methods can be used to charge a metal sphere positively without touching it . Select the best

A
Connect the positive terminal of a battery and float the other end of the battery

B
Rub it with a piece of fur

C
Bring a negatively charged rod near the sphere and touch it to ground for a short while

D
Rub it with a piece of silk

Solution

This can be possible by induction, if a negative charge rod is placed near the sphere (at a distance not in touch) than it attracts positive charge inside the sphere towards its side and the negative charges collected on other side and when the surface of sphere connected to earth than the negative charge goes to earth and the sphere remain positively charged.
Question 2
4 / -1

When a negatively charged conductor is connected to earth,

A
No charge flow occurs.

B
Protons flow from the conductor to the earth.

C
Electrons flow from the earth to the conductor.

D
Electrons flow from the conductor to the earth.

Solution

After earthing a positively charged conductor electrons flow from earth to conductor and if a negatively charged conductor is earthed then electrons flows from conductor to earth.
Question 3
4 / -1

A point charge of 2.0 μC is at the centre of a cubic Gaussian surface 9.0 cm on edge. What is the net electric flux through the surface?

A
1.7×10⁵Nm²/C

B
2.1×10⁵Nm²/C

C
2.2×10⁵Nm²/C

D
1.9×10⁵Nm²/C

Solution
Question 4
4 / -1

Two identical conductors of copper and aluminium are placed in an identical electric field. The magnitude of induced charge in the aluminium will be:

A
Zero

B
Equal to that of copper

C
Greater than in copper

D
less than in copper

Solution

As aluminium and copper are metals, their mobile electrons move under the influence of the external field until they reach the surface of the metal and collect there. External electric fields induce surface changes on metal objects that exactly cancel the field within. Since the field applied is same in both case, the induced charge will be the same. Hence, the magnitude of induced charge in the aluminium will be the same as that of copper.
Question 5
4 / -1

A point charge causes an electric flux of −1.0×10³Nm²/C to pass through a spherical Gaussian surface of 10.0 cm radius centred on the charge.
(a) If the radius of the Gaussian surface were doubled, how much flux would pass through the surface?
(b) What is the value of the point charge?

A
10³Nm²/C,−7.8nC

B
10³Nm²/C,−8.8nC

C
−10³Nm²/C,−8.8nC

D
−10³Nm²/C,−6.8nC

Solution

Electric flux is given by since amount of charge not depends on size and shape so by making radius < double the amount of charge remain same so electric flux remain same.
Question 6
4 / -1

Electric charge:

A
Is a property of protons only.

B
Is a property of particles such as atoms, ions, electrons, etc.

C
Is a property of neutrons only.

D
Is a property of electrons only.

Solution

Electric charge, the basic property of matter carried by some elementary particles, such as atoms; ions; electrons; etc, that govern how the particles are affected by an electric or magnetic field.
Electric charge, which can be positive or negative, occurs in discrete natural units and is neither created nor destroyed.
Question 7
4 / -1

An electric dipole is

A
A pair of electric charges of equal magnitude q separated by a distance d

B
A pair of electric charges of equal magnitude q but positive sign, separated by a distance d

C
A pair of electric charges of equal magnitude q but opposite sign, separated by a distance

D
A pair of electric charges of equal magnitude q but negative sign, separated by a distance d

Solution

An electric dipole is a separation of positive and negative charges. The simplest example of this is a pair of electric charges of equal magnitude but opposite sign, separated by some (usually small) distance. A permanent electric dipole is called an electret.
Question 8
4 / -1

A hollow spherical conductor of radius 2m carries a charge of 500 μ C. Then electric field strength at its surface is

A
4.5×10⁶N/C

B
Zero

C
2.25×10⁶N/C

D
1.125×10⁶N/C .

Solution
Question 9
4 / -1

For forming an electric dipole between two point charges separated by a small distance, the two point charges are of

A
Unequal magnitude and opposite sign

B
Unequal magnitude but same sign

C
Equal magnitude and same sign

D
Equal magnitude but opposite sign

Solution

An electric dipole is tagged as a pair of objects which possess equal & opposite charges, parted by a significantly small distance.
Question 10
4 / -1

The amount of work done in moving a charge from one point to another along an equipotential line or surface charge is

A
Zero

B
Infinity

C
One

D
Two

Solution

Since Potential difference between two points in equipotential surfaces is zero , the work done between two points in equipotential surface is also zero .