Oscillations Te...

The displacement equation of a particle is x = 3 sin 2t + 4 cos 2t. The amplitude and maximum velocity will be respectively

A simple harmonic oscillator has a period of 0.01 s and an amplitude of 0.2 m. The magnitude of the velocity in m sec^–1 at the centre of oscillation is

A particle executes S.H.M. with a period of 6 second and amplitude of 3 cm. Its maximum speed in cm/s is

A S.H.M. has amplitude \'a\' and time period T. The maximum velocity will be

If the displacement of a particle executing S.H.M. is given by y = 0.30 sin (220t + 0.64) in metre, then the frequency and maximum velocity of the particle is

A particle executes simple harmonic motion with a time period of 16 s. At time t = 2 s, the particle crosses the mean position while at t = 4s, its velocity is 4 ms^–1. The amplitude of motion in metre is

The amplitude of a particle executing S.H.M. is 4 cm. At the mean position the speed of the particle is 16 cm/s. The distance of the particle from the mean, position at which the speed of the particle becomes 8√3 cm/s, will be

The maximum velocity of a particle executing S.H.M. is V. If the amplitude is doubled and the time period of oscillation decreased to 1/3 of its original value, the maximum velocity becomes