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Oscillations Test - 29

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Oscillations Test - 29
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  • Question 1
    4 / -1
    A particle executing simple harmonic motion with amplitude of 0.1 m. At a certain instant when its displacement is 0.02 m, its acceleration is 0.5 m/s2. The maximum velocity of the particle is (in m/s)
    Solution

  • Question 2
    4 / -1

    Solution

  • Question 3
    4 / -1
    A particle executes linear simple harmonic motion with an amplitude of 2 cm. When the particle is at 1 cm from the mean position the magnitude of its velocity is equal to that of its acceleration. Then, its time period in seconds is
    Solution

  • Question 4
    4 / -1
    In simple harmonic motion, the ratio of acceleration of the particle to its displacement at any time is a measure of
    Solution

  • Question 5
    4 / -1
    The maximum velocity and the maximum acceleration of a body moving in a simple harmonic oscillator are 2 m/s and 4 m/s2. Then angular velocity will be
    Solution

  • Question 6
    4 / -1

    Solution

  • Question 7
    4 / -1
    If a simple pendulum has significant amplitude (up to a factor or 1/e of original) only in the period between t = 0s to t = τs, then τ may be called the average life of the pendulum. When the spherical bob of the pendulum suffers a retardation (due to viscous drag) proportional to its velocity, with \'b\' as the constant of proportionality, the average life time of the pendulum is (assuming damping is small) in seconds
    Solution

  • Question 8
    4 / -1
    A particle is vibrating in a simple harmonic motion with an amplitude of 4 cm. At what displacement from the equilibrium position, is its energy half potential and half kinetic
    Solution

  • Question 9
    4 / -1
    If a body is executing simple harmonic motion, then
  • Question 10
    4 / -1
    The potential energy of a particle with displacement X is U(X). The motion is simple harmonic, when (K is a positive constant)
    Solution

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