Oscillations Test

Result

Oscillations Test - 32

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Weekly Quiz Competition

Question 1
4 / -1

A

B

C

D

Solution
Question 2
4 / -1

The motion of a particle executing S.H.M. is given by x = 0.01 sin 100 π(t + 0.5), where x is in metres and time is in seconds. The time period is

A
0.01 s

B
0.02 s

C
0.1 s

D
0.2 s

Solution
Question 3
4 / -1

The kinetic energy of a particle executing S.H.M. is 16 J when it is in its mean position. If the amplitude of oscillations is 25 cm and the mass of the particle is 5.12 kg, the time period of its oscillation is

A

B

C

D

Solution
Question 4
4 / -1

The acceleration of a particle performing S.H.M. is 12 cm/s² at a distance of 3 cm from the mean position. Its time period is

A
0.5 s

B
1.0 s

C
2.0 s

D
3.14 s

Solution
Question 5
4 / -1

A
0.5 Hz

B
1.0 Hz

C
1.5 Hz

D
2.0 Hz

Solution
Question 6
4 / -1

What is constant in S.H.M.

A
Restoring force

B
Kinetic energy

C
Potential energy

D
Periodic time
Question 7
4 / -1

If a simple harmonic oscillator has got a displacement of 0.02 m and acceleration equal to 2.0 ms^–2 at any time, the angular frequency of the oscillator is equal to

A
10 rad s^–1

B
0.1 rad s^–1

C
100 rad s^–1

D
1 rad s^–1

Solution
Question 8
4 / -1

A particle executes S.H.M. in a line 4 cm long. Its velocity when passing through the centre of line is 12 cm/s. The period will be

A
2.047 s

B
1.047 s

C
3.047 s

D
0.047 s

Solution
Question 9
4 / -1

Two particle A and B execute simple harmonic motion of period T and 5T/4. They start from mean position. The phase difference between them when the particle A complete an oscillation will be

A
π/2

B
0

C
2 π /5

D
π /4

Solution
Question 10
4 / -1

A simple harmonic wave having an amplitude a and time period T is represented by the equation y = 5 sin π(t + 4) m. Then the value of amplitude (a) in (m) and time period (T) in second are

A
a = 10, T = 2

B
a = 5, T = 1

C
a = 10, T = 1

D
a = 5, T = 2

Solution