Oscillations Test

Result

Oscillations Test - 35

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Weekly Quiz Competition

Question 1
4 / -1

Length of a simple pendulum is l and its maximum angular displacement is θ, then its maximum K.E. is

A
mgl sin θ

B
mgl(1 + sin θ)

C
mgl(1 + cos θ)

D
mg1(1 – cos θ)

Solution
Question 2
4 / -1

The height of a swing changes during its motion from 0.1 m to 2.5 m. The minimum velocity of a boy who swings in this swing is

A
5.4 m/s

B
4.95 m/s

C
3.14 m/s

D
Zero
Question 3
4 / -1

The amplitude of an oscillating simple pendulum is 10 cm and its period is 4 s. Its speed after 1 s after it passes its equilibrium position, is

A
Zero

B
0.57 m/s

C
0.212 m/s

D
0.32 m/s

Solution
Question 4
4 / -1

A pendulum of length 2 m lift at P. When it reaches Q, it losses 10% of its total energy due to air resistance. The velocity at Q is

A
6 m/s

B
1 m/s

C
2 m/s

D
8 m/s

Solution
Question 5
4 / -1

The periodic time of a simple pendulum of length 1 m and amplitude 2 cm is 5 seconds. If the amplitude is made 4 cm, its periodic time in seconds will be

A
2.5

B
5

C
10

D
Question 6
4 / -1

The ratio of frequencies of two pendulums are 2 : 3, then their length are in ratio

A

B

C
4/9

D
9/4

Solution
Question 7
4 / -1

A simple pendulum hanging from the ceiling of a stationary lift has a time period T₁. When the lift moves downward with constant velocity, the time period is T₂, then

A
T₂ is infinity

B
T₂ > T₁

C
T₂ < T₁

D
T₂ = T₁

Solution
Question 8
4 / -1

If the length of a pendulum is made 9 times and mass of the bob is made 4 times then the value of time period becomes

A
3T

B
3/2T

C
4T

D
2T

Solution
Question 9
4 / -1

A simple pendulum is suspended from the ceiling of a stationary elevator and its period of oscillation is T. The elevator is then set into motion and the new time period is found to be longer. Then the elevator is

A
Accelerated upward

B
Accelerated downward

C
Moving downward with non-uniform speed

D
Moving downward with uniform speed
Question 10
4 / -1

A pendulum bob of mass m is hanging from a fixed point by a light thread of length l. A horizontal speed v₀ is imparted to the bob so that it takes up horizontal position. If g is the acceleration due to gravity, then v₀ is

A
mgl

B

C

D
gl

Solution